PLZZ HELP! I got 143 as my answer, but that was incorrect.

Anvisha [2.4K]

Y=50-3.25X after 12 lunches it would have a value of 11$

4 0

3 years ago

Paul's bank account used to have $1,250 dollars in it. After saving and following a strict budget he manages to increase that am

hichkok12 [17]

Answer: $1750

Step-by-step: see the picture

Please mark me brainliest!! :)

6 0

3 years ago

Convert 30 feet per second to miles per minute.

Amanda [17]

We know that:

1 mile = 5280 ft

1 minute = 60 sec

Therefore to convert this we simply use the conversion factors:

(30 ft / s) * (60 s / 1 min) * (1 mi / 5280 ft) = 0.34 mi / min

So we got 0.34 miles per minute.

8 0

3 years ago

PLEASE HELP ME!!!

IgorC [24]

Answer:

Option A) Inside the circle

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The radius is equal to the distance from the center to any point on the circle

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

A(-5,-8),M(-1,-3)

substitute the values

$r=\sqrt{(-3+8)^{2}+(-1+5)^{2}}$

$r=\sqrt{(5)^{2}+(4)^{2}}$

$r=\sqrt{41}\ units$

step 2

Find the distance from the center to point V

we know that

If the distance from the center to point V is equal to the radius, then the point V lie on the circle

If the distance from the center to point V is less than the radius, then the point V lie inside the circle

If the distance from the center to point V is greater than the radius, then the point V lie outside the circle

we have

A(-5,-8),V(-11,-6)

substitute in the formula

$d=\sqrt{(-6+8)^{2}+(-11+5)^{2}}$

$d=\sqrt{(2)^{2}+(-6)^{2}}$

$d=\sqrt{40}\ units$

so

$\sqrt{40}\ units< \sqrt{41}\ units$

The distance from the center to point V is less than the radius

therefore

The point V lie inside the circle

4 0

4 years ago

Prompt

Dafna1 [17]

Answer:

1. Anya's suggestion will create the larger volume

2. x is limited to 0 < x < 4.25 because 8.5 - 2x > 0

Step-by-step explanation:

- Lets explain how to solve the problem

- The dimensions of the cardboard are 11 inches by 8.5 inches

- A small square of the same size is cut from each corner, and each

side folded up along the cuts to from a box with no lid

- The formed solid will be a rectangular solid of three dimensions,

length , width and height

- The volume of the solid is V = length × width × height

1.

- Anya thinks the cut should be 1.5 inches to create the greatest

volume, while Terrence thinks it should be 3 inches

- Lets find the formula for the volume of both

∵ The length of the sheet is 11 inches

∵ The width of the sheet is 8.5

- We will cut x from each corner

∴ The length of the base of the box = 11 - 2x

∴ The width of the base of the box = 8.5 - 2x

∵ The height of the box is x

∴ The volume of the box = (11 - 2x) × (8.5 - 2x) × x

∴ The formula for the volume of both is V = x(11 - 2x)(8.5 - 2x)

∵ Anya thinks the cut should be 1.5 inches

∴ x = 1.5

∴ V = 1.5(11 - 2×1.5)(8.5 - 2×1.5)

∴ V = 1.5(11 - 3)(8.5 - 3)

∴ V = 1.5(8)(5.5) = 66 inches³

* The volume of Anya's box is 66 inches³

∵ Terrence thinks the cut should be 3 inches

∴ x = 3

∴ V = 3(11 - 2×3)(8.5 - 2×3)

∴ V = 3(11 - 6)(8.5 - 6)

∴ V = 3(5)(2.5) = 37.5 inches³

∴ The volume of Terrence box is 37.5 inches³

* Anya's suggestion will create the larger volume

∵ The volume of the box depends on the dimensions of its base

and its height

∴ We can make from the same cardboard many boxes with different

dimensions by cutting small squares of the same size from its four

corners with different sides (chose different values of x)

2.

∵ The small dimension of the cardboard is 8.5 inches

∵ We will cut x from its corners

∵ The new dimension will be 8.5 - 2x

- The new dimension must be greater than 0

∴ 8.5 - 2x > 0 ⇒ add 2x for both sides

∴ 8.5 > 2x ⇒ divide both sides by 2

∴ 4.25 > x

∴ x must be greater than 0 inch and smaller than 4.25 inches

* x is limited to 0 < x < 4.25 because 8.5 - 2x > 0

4 0

3 years ago