Q.

Alicia drove at a constant speed and travel 183 miles in three hours How many miles what Alicia travel in 11 hours at the same s

Natalka [10]

Answer:You'll find that x = 671 miles

Step-by-step explanation:

Setting up and solving an equation of ratios is one of the fastest ways in which to solve this kind of probelm.

183 miles 3 hrs

-------------- = ------------

x 11 hrs

4 0

3 years ago

Which one ? please help!

Ber [7]

Answer:

the first or third one

Step-by-step explanation:

5 0

3 years ago

A submarine drops 3 feet every minute. If it started at sea level, which integer could represent the submarine's location after

irina [24]

Answer:

The submarine should be at 15 feet is it continued to drop 3 feet every minute at a continuous rate.

Step-by-step explanation:

3 x 5 = 15 (ft.)

4 0

3 years ago

Write the equation of the quadratic function with roots 6 and 10 and a vertex at (8,2)

Elis [28]

...6 and 10 are roots, so x – 6 and x – 10 are factors.
y = a(x – 6)(x – 10).....plug in the point (8, 2) and solve for a:
2 = a(8 – 6)(8 – 10)
2 = –4a
a = –1/2
...y = (–1/2)(x – 6)(x – 10)
...y = (–1/2)(x² – 16x + 60)
...y = (–x²/2) + 8x – 30 <<<------Answer, or:
...y = (–1/2)(x – 8)² + 2 <<<------Answer

7 0

4 years ago

A powder diet is tested on 49 people, and a liquid diet is tested on 36 different people. Of interest is whether the liquid diet

brilliants [131]

Answer:

There is not enough evidence to support the claim that the liquid diet yields a higher mean weight loss than the powder diet (P-value = 0.15).

Step-by-step explanation:

This is a hypothesis test for the difference between populations means.

The claim is that the liquid diet yields a higher mean weight loss than the powder diet.

Then, the null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2< 0$

The significance level is 0.05.

The sample 1 (powder diet group), of size n1=49 has a mean of 42 and a standard deviation of 12.

The sample 2 (liquid diet group), of size n2=36 has a mean of 45 and a standard deviation of 14.

The difference between sample means is Md=-3.

$M_d=M_1-M_2=42-45=-3$

The estimated standard error of the difference between means is computed using the formula:

$s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{12^2}{49}+\dfrac{14^2}{36}}\\\\\\s_{M_d}=\sqrt{2.939+5.444}=\sqrt{8.383}=2.895$

Then, we can calculate the t-statistic as:

$t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{-3-0}{2.895}=\dfrac{-3}{2.895}=-1.04$

The degrees of freedom for this test are:

$df=n_1+n_2-1=49+36-2=83$

This test is a left-tailed test, with 83 degrees of freedom and t=-1.04, so the P-value for this test is calculated as (using a t-table):

$\text{P-value}=P(t$

As the P-value (0.15) is greater than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that the liquid diet yields a higher mean weight loss than the powder diet.

6 0

3 years ago

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