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3 years ago

10

Calculate the area of triangle ABC with altitude AD, given A(-5, 4), B(-6, 1), C(0, 1), and D(-5, 1).

1 answer:

snow_lady [41]3 years ago

3 0

Answer:

the area of triangle ABC = 9

Step-by-step explanation:

Check the photo below for the details.

:)

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Monday 2/3 of the team practiced, Tues 7/8, Wed 1/2,Thurs 3/4. On which day were the most team members present at practice?

MrMuchimi

Tuesday.

1/2 =50%, 3/4=75% 2/3=66.6% and so forth.

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How many different combinations of shirts and ties are possible if you have 4 shirts and 5 ties?

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What is a y-intercept of the graphed function?

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(0,-9) is the y intercept

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3 years ago

20% of city employees ride the bus to work. This is up 10% from last year. What percent of employees rode the bus to work last y

Pepsi [2]

Answer:

18.18% of employees rode the bus to work last year

Step-by-step explanation:

This question can be solved using a rule of three.

Last year, a proportion of x employees riding the bus was 100% = 1.

This year, 20% = 0.2 ride the bus, which is 100 + 10 = 110% = 1.1 of last year.

So

0.2 - 1.1

x - 1

$1.1x = 0.2$

$x = \frac{0.2}{1.1}$

$x = 0.1818$

0.1818*100 = 18.18%

18.18% of employees rode the bus to work last year

4 0

3 years ago

Match each series with the equivalent series written in sigma notation

PIT_PIT [208]

Answer:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

Step-by-step explanation:

Given

See attachment for complete question

Required

Match equivalent expressions

Solving (a):

$3 + 12 + 48 + 192 + 768$

The expression can be written as:

$3 \to 3*4^{0$ --- 0

$12 \to 3 * 4^{1$ ---- 1

$48 \to 3 * 4^{2$ --- 2

$192 \to 3 * 4^{3$ ---- 3

$768 \to 3 * 4^{4$ ---- 4

For the nth term, the expression is:

$Term = 3 * 4^{n$ ---- n

So, the summation is:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

Solving (b):

$4 + 32 + 256 + 2048 + 16384$

The expression can be written as:

$4 \to 4 * 8^0$ --- 0

$32 \to 4 * 8^1$ ---- 1

$256 \to 4 * 8^2$ --- 2

$2048 \to 4 * 8^3$ ---- 3

$16384 \to 4 * 8^4$ ---- 4

For the nth term, the expression is:

$Term \to 4 * 8^n$ ---- n

So, the summation is:

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

Solving (c):

$2 + 6 + 18 + 54 + 162$

The expression can be written as:

$2 \to 2 * 3^0$ --- 0

$6 \to 2 * 3^1$ ---- 1

$18 \to 2 * 3^2$ --- 2

$54 \to 2 * 3^3$ ---- 3

$162 \to 2 * 3^4$ ---- 4

For the nth term, the expression is:

$Term \to 2 * 3^n$ ---- n

So, the summation is:

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

Solving (d):

$3 + 15 + 75 + 375 + 1875$

The expression can be written as:

$3 \to 3 * 5^0$ --- 0

$15 \to 3 * 5^1$ ---- 1

$75 \to 3 * 5^2$ --- 2

$375 \to 3 * 5^3$ ---- 3

$1875 \to 3 * 5^4$ ---- 4

For the nth term, the expression is:

$Term \to 3 * 5^n$ ---- n

So, the summation is:

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

5 0

2 years ago