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3 years ago

Calculate the area of triangle ABC with altitude AD, given A(-5, 4), B(-6, 1), C(0, 1), and D(-5, 1).

Mathematics

1 answer:

snow_lady [41]3 years ago

3 0

Answer:

the area of triangle ABC = 9

Step-by-step explanation:

Check the photo below for the details.

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Let ƒ(x) = 5x − l and g(x) = x2 - 1. find (f ○ g)(−7)

attashe74 [19]

Answer:

240

Step-by-step explanation:

5(x² - 1)

5 ((-7)² - 1)

5(49 - 1)

5 (48)

4 0

2 years ago

Solve the following equation -6p+7=3(2p-3)-4(-10+4p)<br> a.p=6<br> b.p=5<br> c.p=7<br> d.p=12

Ilia_Sergeevich [38]

Solve for p by simplifying both sides of the equation, then isolating the variable.
p=6

7 0

3 years ago

Use rulers and compasses to draw a line which is perpendicular to line AB at point C

netineya [11]

Answer:

Draw a line AB

Take a point C on AB

Fix the tip of compass at C and with a fix radius, cut AB on both sides of C

Mark those points D and E

Fix the tip of compass on D, and with the same radius, draw an arc above C

Do the same with E

Those two arcs will intersect at a point, mark the point F

Make a line passing through both C and F

Line CF is perpendicular to AB

8 0

2 years ago

Are these lines parallel perpendicular or neither

Natasha_Volkova [10]

Answer:

perpendicular

Step-by-step explanation:

start but putting each line into the standard line format

2x-y=-5

-y=-2x-5

y=2x+5

x+2y=-6

2y=-x-6

y=-(1/2)x-3

if lines are parallel the slopes would be the same. 2 is not equal to -1/2

if lines are perpendicular the slope of one would be the opposite inverse of the other.

negative inverse of 2 = - (1/2)

so the lines are perpendicular

8 0

3 years ago

If f(x-3)=x^2-4x+5, what's f(1-x)

olganol [36]

Answer:

$\large\boxed{f(1-x)=x^2-4x+5}$

Step-by-step explanation:

$f(x-3)=x^2-4x+5\\\\f((x-3)+3)\to\text{put x + 3 to the equation of the function:}\\\\f(x-3+3)=(x+3)^2-4(x+3)+5\\\text{use the distributive property and}\ (a+b)^2=a^2+2ab+b^2\\f(x)=x^2+2(x)(3)+3^2+(-4)(x)+(-4)(3)+5\\f(x)=x^2+6x+9-4x-12+5\qquad\text{combine like terms}\\f(x)=x^2+(6x-4x)+(9-12+5)\\f(x)=x^2+2x+2\\\\f(1-x)\to\text{put 1 - x to the equation of the funtion f(x):}\\\\f(1-x)=(1-x)^2+2(1-x)+2\\\text{use the distributive property and}\ (a-b)^2=a^2-2ab+b^2$

$f(1-x)=1^2-2(1)(x)+x^2+(2)(1)+(2)(-x)+2\\f(1-x)=1-2x+x^2+2-2x+2\qquad\text{combine like terms}\\f(1-x)=x^2+(-2x-2x)+(1+2+2)\\f(1-x)=x^2-4x+5$

4 0

3 years ago