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Tpy6a [65]
3 years ago
9

3. How are the long DNA molecules found in eukaryotes packed into short chromosomes?

Biology
1 answer:
AysviL [449]3 years ago
8 0

Explanation:

DNA is tightly wound around histones,forming nucleosomes. Nucleosomes are tightly coiled and supercoiled to form chromosomes.

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2. Which diagram best illustrates an event in
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Answer:

4

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Because a female sex organ live the ovum shown needs to be in contact with the male sex organ the sperm to fertilize and being in the process of making said human

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3 years ago
Solar tracking, or _____, is a plant's growth toward light.
GrogVix [38]
Phototropism as photo means light
eg: photosynthesis
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4 years ago
Which of the following factors would have the smallest impact on a population’s size? a. the total number of organisms b. the av
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D

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adequate shelter, as animals can live without adequate shelter.

8 0
4 years ago
In Drosophila, vestigial (partially formed) wings (vg) are recessive to normal long wings (vg+) and the gene for this trait is a
Marina CMI [18]

Answer/ Explanation:

a. The genotype of a homozygous white eyed long winged female would be Vg+Vg+XrXr. We denote the white allele as recessive (r) because the XY male only has one copy and yet has red eyes, so the red eye trait (R) must be dominant. A homozygous red eyed vestigial winged male would have be VgVgXRY. The possible gametes for the female are Vg+Xr only. For the male, the possible gametes are VgXR or VgY

The attached punnett square shows the results of the cross. The females will all be Vg+VgXRXr. The males will all be Vg+VgXRY (must inherit Y from father). That means they will all  have normal length wings, the males will have white eyes and the females will have red eyes.

b. The F2 flies arise from intercrossing the F1, so the cross will be Vg+VgXRXr x Vg+VgXRY. The possible gametes for the mother are: Vg+XR, Vg+Xr, VgXR or VgXr. The possible gametes for the father are Vg+Xr

, Vg+Y

, VgXr

, VgY

. The attached punnet square shows this cross. The ratio of the phenotypes will be 6:6:2:2, or 3:3:1:1 (long-winged red eye: long-winged white eye: vestigial wing red eye: vestigial wing white eye), genotypes shown in the attachment.

c. F1 cross back to the mother would be Vg+VgXRY x Vg+Vg+XrXr. The genotypes are shown in the attached punnet square. The offspring will all be long-winged with white eyes. The F1 to the father would be Vg+VgXRXr x VgVgXRY. The ratio would be 3:3:1:1 long-winged red eye: long-winged white eye: vestigial wing red eye: vestigial wing white eye

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7 0
3 years ago
How has Charles Darwin contributed to the study of evolution?
Nat2105 [25]
The answer is A
he is known as the father of natural selection  :D
4 0
3 years ago
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