Answer:
−35.713332 ; 0.313332
Step-by-step explanation:
Given that:
Sample size, n1 = 11
Sample mean, x1 = 79
Standard deviation, s1 = 18.25
Sample size, n2 = 18
Sample mean, x2 = 96.70
Standard deviation, s2 = 20.25
df = n1 + n2 - 2 ; 11 + 18 - 2 = 27
Tcritical = T0.01, 27 = 2.473
S = sqrt[(s1²/n1) + (s2²/n2)]
S = sqrt[(18.25^2 / 11) + (20.25^2 / 18)]
S = 7.284
(μ1 - μ2) = (x1 - x2) ± Tcritical * S
(μ1 - μ2) = (79 - 96.70) ± 2.473*7.284
(μ1 - μ2) = - 17.7 ± 18.013332
-17.7 - 18.013332 ; - 17.7 + 18.013332
−35.713332 ; 0.313332
Answer:
B
How many times greater in the area of the signal from transmitter
I hope you find the answer I needed points quickly I’m doing a timed quiz I apologize
<span>7y-4y-5y
7y-9y
-2y
...........</span>
Answer:
1. 75 feet
2. 27 seconds
Step-by-step explanation:
1. If six seconds is equal to 10 feet that means that 42 seconds is equal to 70 feet (6 X 7 = 42) It also means that 3 seconds is equal to 5 feet. (42 + 3 = 45)
2. If 6 seconds is 10 feet, then 6 X 4 is 40 feet (24) And since 5 feet is equal to 3 seconds then we get 24 + 3 = 27
