The value of x such that f(x) = g(x) is x = 3
<h3>Quadratic equation</h3>
Given the following expressions as shown
f(x) = x^3-3x^2+2 and;
g(x) = x^2 -6x+11
Equate the expressions
x^3-3x^2+2 = x^2 -6x+11
Equate to zero
x^3-3x^2-x^2+2-11 = 0
x^3-3x^2-x^2 + 6x - 9 = 0
x^3-4x^2+6x-9 = 0
Factorize
On factorizing the value of x = 3
Hence the value of x such that f(x) = g(x) is x = 3
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Answer:
m∠5 = 44°; m∠7 = 44°
Step-by-step explanation:
Angle 4 and 1 are supplementary (they make up a line) and their sum is equal to 180 degrees.
Subtracting the measure of angle 4 from 180 degrees gives the measure of angle 1. (180 - 136 = 44).
So Angle 1's measure is 44 degrees.
According to the Corresponding Angle Postulate, Angle 1 and Angle 5 are congruent. Therefore, m∠5 = 44°
According to the Vertical Angles Postulate (if two angles are vertical, they are congruent), ∠5 ≅ ∠7, meaning that m∠5 = m∠7.
So m∠7 = 44°
Answer:
A.
Step-by-step explanation:
First find the sum
Now, find the probabilities:
Hence, the frequency distribution table is
Volume = w * 2w * 3w = 6w^3 cubic units
58.635 rounded to the nearest hundreth is:
58.6 because 3 is less than 5
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