<span>What are the characteristics of a radical equation?
Radical equations are those equations where the variable is inside a radical.
For example: √x - 5 = 0 is a radical equation but x -√5 = 0 is not a radical equations.
How is solving radical equations similar to solving linear equations?
You search to isolate the variable, by performing identical operations on both sides of the equation.
Why is it important to check the solutions to a radical equation?
This is important when the index of the root is an even number. For example 2. When you square a square root you force the results to be positive and this may hide the real condition of the original equation.
For example, √x + 5 = 0
=> √x = -5
=>(√x)^2 = (-5)^2
=> x = 25
When you check: √x + 5 =√25 + 5 = 5 + 5 = 10 which is contradictory with the original equation. You have to discard the solution, becasue none real number exists whose square root is negative, which means that √x + 5 = 0 does not have a real solution.
Create your own radical equation. Describe in complete sentences and demonstrate the process in finding its solution(s)
√(3x+1) - 10 = 0
1) isolate the radical: √(3x + 1) = 10
2) Square both sides: [√(3x + 1)]^2 = 10^2
=> 3x + 1 = 100
=> 3x = 99
=> x = 33
3) Check
√[(3(33) + 1] - 10 = √(99 + 1) - 10 = √100 - 10 = 10 - 10 = 0
Then the solution is correct
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Answer:
Step-by-step explanation:
Put the square roots together
4*5 * sqrt(14z^2 * 21z^3)
4*5 * sqrt(2*7 * z^2 * 3*7 z^2 * z)
The rule is to remove the perfect square from under the square root sign, you take 1 member of the perfect square out of the root sign, and throw the other one away. If there are an odd number of factors under the root sign, leave one of them alone.
4*5 * 7 z * z sqrt(2 * 3 * z)
140 z^2 * sqrt(6z)
Answer:
20km/hr
Step-by-step explanation:
Given that a ship sailed 30km in one and a half hours. We need to find out the rate of ship in kilometres/hour . The rate is also called Speed.
<u>Speed</u><u>:</u><u>-</u> Distance travelled per unit time is called Speed .
Here , according to Question,
<u>Distance</u> = 30 km
<u>Time </u> = 1½ hrs .
We know that ,
Subsequently ,
Substitute the respective values ,
We can write 1.5 as 3/2 , therefore ,
Simplify the RHS ,
<u>Hence</u><u> the</u><u> </u><u>Rate/</u><u>Speed </u><u>of</u><u> the</u><u> </u><u>ship </u><u>is </u><u>2</u><u>0</u><u>k</u><u>m</u><u>/</u><u>hr </u><u>.</u>