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3 years ago

Help me please these Recharf

1 answer:

RSB [31]3 years ago

6 0

I’m not to sure sorry good luck

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Lapatulllka [165]

$(x-1)^3 (4x-9) - (16x+9) (x+1)^2$

$= (x^3-3x^2+3x-1) (4x-9) - (16x+9) (x^2+2x+1)$

$= (4x^4-12x^3+12x^2-4x-9x^3-27x^2-27x+9)-(16x^3+32x^2+16x+9x^2+18x+9)$

$= (4x^4-21x^3+39x^2-31x+9)-16x^3-32x^2-16x-9x^2-18x-9$

$= 4x^4-21x^3+39x^2-31x+9-16x^3-32x^2-16x-9x^2-18x-9$

$= 4x^4-37x^3-2x^2-65x$

$= x(4x^3-37x^2-2x-65)$

hence final factor is $x(4x^3-37x^2-2x-65)$

5 0

3 years ago

ELEN [110]

0.1 i guess ok so try my question but im not 100 sure its correct

3 0

4 years ago

Tema [17]

Answer:

7.66666666667

Step-by-step explanation:

8 0

3 years ago

kifflom [539]

5 since 40 divided by 8 is 5.

3 0

3 years ago

Finger [1]

Step-by-step explanation:

this will help you

if not correct please tell me

7 0

3 years ago