How many arrangements of three digits can be formed from the digits zero through nine
1 answer:
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Answer:
B.
Step-by-step explanation:
First we must find the x and y intercepts for y = -2x - 4. The y-intercept is -4, since it is b in y = mx + b, but you can also find it by plugging in zero for x:
The x-intercept is found by plugging in zero for y:
The graph with an x-intercept of -2 and a y-intercept of -4 is C. Also, less than inequalities have the shading underneath the line, so we definitely know C is the answer.
Answer:
a) P(three tails) =
b) P(two tails followed by one head) =
Step-by-step explanation:
coin is tossed three times so, outcome is
HHH, TTT, HTH, THH, HHT, THT, TTH, HTT.
Hence sample space will be
S = {HHH, TTT, HTH, THH, HHT, THT, TTH, HTT}
chance of getting three tails is '1' i.e. TTT
hence,
P(three tails) =
two tails followed by one head is TTH
so, chance of getting that outcome is also '1'
hence,
P(two tails followed by one head) =