Answer:
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Probability that 2 of the 10 chargers will be defective =0.35
Number of ways of selecting 10 chargers from 20 chargers is 20C10
20C10 = 184756
Number of ways of selecting 10 chargers from 20 = 184756
Number of ways of selecting 2 defective chargers from 5 defective chargers = 5C2
5C2 = 10
Since 2 defective chargers have been chosen, there remains 8 to choose
Number of ways of selecting 8 good chargers from 15 remaining chargers = 15C8
Number of ways of selecting 8 good chargers from 15 remaining chargers = 6435
Probability that 2 of the 10 will be defective =
(10x6435)/184756
Probability that 2 of the 10 will be defective = 64350/184756
Probability that 2 of the 10 chargers will be defective =0.35
Learn more on probability here: brainly.com/question/24756209
Answer:
$152.33
Step-by-step explanation:
123.85 x 0.05 = $6.19
123.85 x 0.18 = $22.29
123.85 + 6.19 + 22.29 = $152.33
The function is graphed as shown below
Part A:
We use the formula

to find the vertex of the function. A quadratic function of the form of

and equating this form to the given function

, we have

and

.
Substituting

and

into the vertex formula, we have

, as shown in the graph
This calculation means that the highest profit is achieved when the number of photo printed equals to ten photos
Part B:
We can find solution to this equation by factorising





and

, as shown in the graph
The two values means that the company makes no profit when they either produce 5 or 15 photos