<h2>
Range of x </h2><h3>
and x>6</h3><h3>
Step-by-step explanation:</h3>
Given AB = 4x + 5, BC = 3x - 2 and AC 9x -5
The sum of the length of any two sides of a triangle is greater than the length of third side.
Case I
AB + BC > AC
⇔4x +5 +3x -2 > 9x -5
⇔7x + 3 >9x - 5
⇔ 7x -9x > -5 -3
⇔-2x > -8
⇔x <4
Case II
if AB+AC > BC
4x +5 +9x -5> 3x -2
⇔13x >3x -2
⇔ 13x -3x> -2
⇔10x > -2
⇔x >
Case III
AC+BC > AB
⇔9x - 5 +3x - 2 > 4x +5
⇔6x -7 > 4x +5
⇔6x -4x >5+7
⇔2x > 12
⇔x > 6
Answer:1 and 4
Step-by-step explanation:
3/8 x 2/6 = 6/48 which simplified is 1/8
Answer:
Step-by-step explanation:
f(5)=49.5(0.88)^5
f(5)=$26.12
Use the rational zero theorem
In rational zero theorem, the rational zeros of the form +-p/q
where p is the factors of constant
and q is the factors of leading coefficient
In our f(x), constant is 2 and leading coefficient is 14
Factors of 2 are 1, 2
Factors of 14 are 1,2, 7, 14
Rational zeros of the form +-p/q are
Now we separate the factors
We ignore the zeros that are repeating
Option A is correct
