Answer:
25
Step-by-step explanation:
5(n-8)=3n+10
5n-40=3n+10
5n=3n+50
2n=50
n=25
The parts that are missing in the proof are:
It is given
∠2 ≅ ∠3
converse alternate exterior angles theorem
<h3>What is the Converse of Alternate Exterior Angles Theorem?</h3>
The theorem states that, if two exterior alternate angles are congruent, then the lines cut by the transversal are parallel.
∠1 ≅ ∠3 and l║m because we are: given
By the transitive property,
∠2 and ∠3 are alternate interior angles, therefore, they are congruent to each other by the alternate interior angles theorem.
Based on the converse alternate exterior angles theorem, lines p and q are proven to be parallel.
Therefore, the missing parts pf the paragraph proof are:
- It is given
- ∠2 ≅ ∠3
- converse alternate exterior angles theorem
Learn more about the converse alternate exterior angles theorem on:
brainly.com/question/17883766
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Hmmm.....................
Answer:

Step-by-step explanation:
Given
The attached graph
Required
Determine the range of the graph
First, we list out the coordinate of each point on the graph:
The points are:

A function has the form: (x,y)
Where
y = range:
From the coordinate points above,

Order from least to greatest"

Hence, the range are: 
Answer:
- Height = <u>9</u><u> </u>cm which means <u>Option </u><u>C </u>is the answer
Step-by-step explanation:
In the question we are given ,
- Volume of cylinder = <u>2</u><u>2</u><u>5</u><u>π</u><u> </u><u>cm³</u>
- Radius of cylinder = <u>5 cm</u>
And , we have to find the <u>height</u><u> of</u><u> </u><u>cylinder</u><u> </u>.
We know that ,

Our solution starts from here :

<u>Step </u><u>1</u><u> </u><u>:</u> Cancelling π with π :

<u>Step </u><u>2</u><u> </u><u>:</u> Substituting value of radius which is 5 cm in the formula :


<u>Step </u><u>3 </u><u>:</u> Transposing 25 to right hand side :

<u>Step </u><u>4</u><u> </u><u>:</u> Cancelling 225 by 25 :

- <u>Henceforth</u><u> </u><u>,</u><u> </u><u>height</u><u> </u><u>of </u><u>cylinder</u><u> is</u><u> </u><u>9</u><u> </u><u>cm</u>
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<u>#</u><u>K</u><u>e</u><u>e</u><u>p</u><u> </u><u>Learning</u></h2>