Answer:
<em>l = w + 3cm</em>
<em>l = w + 3cmp = 2l + 2w = 58cm</em>
<em>l = w + 3cmp = 2l + 2w = 58cm </em>
<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:</em>
<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58</em>
<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58</em>
<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13</em>
<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 </em>
<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 Plug back in:</em>
<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 Plug back in:l = (13cm) + 3cm = 16cm</em>
<em>l = w + 3cmp = 2l + 2w = 58cm Solve by substitution:2l + 2w = 58 ⇒ 2(w + 3) + 2w = 58⇒ 2w + 6 + 2w = 4w + 6 = 58⇒ 4w = 52 ⇒ w = 13 Plug back in:l = (13cm) + 3cm = 16cmStep-by-step explanation:</em>
I hope this helps you.
Answer:
Length of spaceship in movie = 528
Step-by-step explanation:
Given that:
Drawing ratio of spaceship = 1 : 24
It means that 1 inch on drawing equals 24 inches in movie
Drawing of spaceship = 22 inches
Length of spaceship in movie = x
As the relationship is proportional,
1 : 24 :: 22 : x
Product of mean = Product of extreme
24*22 = x
x = 528
Hence,
Length of spaceship in movie = 528
The table of the probability is missing, so i have attached it.
Answer:
μ = 0.919
The interpretation of this is that;on the average, an individual aged 15 years or older has been involved in 0.919 marriages.
Step-by-step explanation:
The expected value which is also called mean value is denoted by the symbol μ. It is defined as the sum of the product of each possibility x with it's probability P(x) as the formula;
μ = Σx.P(x) = (0 × 0.272) + (1 × 0.575) + (2 × 0.121) + (3 × 0.027) + (4 × 0.004) + (5 × 0.001)
μ = 0.919
Thus, the interpretation of this is that;on the average, an individual aged 15 years or older has been involved in 0.919 marriages.
<em>Answer: i=9</em>
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<em>Step-by-step explanation:</em>
<em>-16=-4(-5+i)</em>
<em>-16=20-4i</em>
<em>-20 -20</em>
<em>-36=-4i</em>
<em>Divide by -4 </em>
<em>i=9</em>
