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hjlf
3 years ago
11

How do you find out GCF (Greatest Common Factor) and LCM (Least Common Multiple)?

Mathematics
1 answer:
Mamont248 [21]3 years ago
7 0
To find the GCF, first you must factor the 2 or more numbers. The GCF is the highest factor the numbers have in common. for example: you have 12 and 8. If you factor out the numbers for 12, you get
1,2,3,4,6,12
For 8, you get:
1,2,4,8
the GCF of this pair is 4 because it is the highest number that goes into both 8 and 12.
To find the LCM, you must find the first number that was multiplied and it must be the same. lets take 3 and 5. Multiply 3 by as many numbers you can think of. For now, lets just go up to 10.
3, 6, 9, 12 15, 18, 21, 24, 27, 30
now to the same for 5:
5, 10, 15, 20, 25, 30, 35, 40, 45, 50
in both 3 and 5, the first set of numbers that match in 30- therefore the LCM of 3 and 5 in 30. I hope this helps!


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If y2 = x3 + 2, which statement is true? The equation is a function at all values of x. The equation is not a function. The equa
tatyana61 [14]

Answer:

The equation is not a function.

Step-by-step explanation:

We are given that

y^2=x^3+2

y=\pm\sqrt{x^3+2}

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Each element of A has unique value in set B.

By definition of  function

In given function

y has no unique value for each value of x.

Substitute x=0

y=\pm \sqrt{0+2}=\pm \sqrt 2

Hence, it is not a function.

6 0
4 years ago
Giải phương trình sau:<br> sinx=1/2
cupoosta [38]

Answer: \begin{bmatrix}\mathrm{Radians:}\:&\:x=\frac{\pi }{6}+2\pi n,\:x=\frac{5\pi }{6}+2\pi n\:\\ \:\mathrm{Degrees:}&\:x=30^{\circ \:}+360^{\circ \:}n,\:x=150^{\circ \:}+360^{\circ \:}n\end{bmatrix}

Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
A particle moves along the curve y = 5x^2 – 1 in such a way that the y value is decreasing at the rate of 2 units per second. At
Shtirlitz [24]

Answer:

The correct option is;

Increasing one fifth unit/sec

Step-by-step explanation:

The equation that gives the curve of the particle of the particle is y = 5·x² - 1

The rate of decrease of the y value dy/dt = 2 units per second

We have;

dy/dx = dy/dt × dt/dx

dy/dx = 10·x

dy/dt = 2 units/sec

dt/dx = (dy/dx)/(dy/dt)

dx/dt = dy/dt/(dy/dx) = 2 unit/sec/(10·x)

When x = 1

dx/dt = 2/(10·x) = 2 unit/sec/(10 × 1) = 1/5 unit/sec

dx/dt = 1/5 unit/sec

Therefore, x is increasing one fifth unit/sec.

8 0
3 years ago
How do i solve -2y=8
Viefleur [7K]
If you're trying to solve for y
-2y = 8
Divide -2 to both sides
\frac{-2y}{-2} =  \frac{8}{-2}
Cancel out the -2 on the left, Divide the -2 to the 8 on the right so
y = -4
4 0
4 years ago
Read 2 more answers
I have five numbers, the mean is 6, and the mode is 7 what could these numbers be?
storchak [24]

Answer:

3, 5, 7, 7, 8

Step-by-step explanation:

3, 5, 7, 7, 8

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the mode = 7

4 0
3 years ago
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