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Ratling [72]
3 years ago
8

Total consumption of fruit juice in a particular country in 2006 was about 1.41 billion gallons. The population of that country

in 2006 was 400 million. What was the average number of gallons of fruit juice consumed per person in the country in 2006? Use pencil and paper. Using the per person amount from this problem, about how many gallons would your class consume?​
Mathematics
1 answer:
Rama09 [41]3 years ago
7 0

Answer:

3.525 gal/person

Step-by-step explanation:

My class would consume 52.875 gallons

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In a week, a given stock gained 6 points, dropped 13 points, dropped 3 points, gained 15 points, and dropped 10 points. What was
Brrunno [24]

6 - 13 - 3 + 15 - 10 = -5

6 0
3 years ago
Write the equation in slope-intercept form, for the line that would coincide with (be in line with) line segment AB.
Llana [10]

Answer:

y=2

Step-by-step explanation:

We are finding the equation of the line that coincide with line segment AB.

So, we can find the equation by using points A and B.

A\rightarrow(-3,2)\\B\rightarrow)(1,2)

Slope of line (m) = \frac{y_2-y_1}{x_2-x_1} = \frac{2-2}{1-(-3)} = 0

Since slope = 0, therefore the line is parallel to x-axis.

The equation of line  is given by y=mx+b

where m is slope and b is y-intercept.

So equation of line AB:

where m=0 and b=2

y=(0)x+2

y=0+2

y=2

8 0
3 years ago
How do you graph y=2x-3 and y=x+2
nadya68 [22]
Start from -3 and do rise over run and the same thing for the other equation but instead of -3 start from 2
5 0
3 years ago
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If Benito is selecting samples of five values from the table, which row will result in the greatest mean? Population Data Row 1
Vilka [71]

Answer:

4th row will result in the greatest mean.

Step-by-step explanation:

We are asked to find the row with greatest mean from our given rows.

We will use formula \bar{x}=\frac{\Sigma x}{n}, where,

\bar{x}=\text{Mean},

\Sigma x=\text{Sum of all data values},

n=\text{Number of data points in sample}

Let us find mean of each row using above formula.

\text{Mean of row 1}=\frac{4+2+2+3+3}{5}

\text{Mean of row 1}=\frac{14}{5}

\text{Mean of row 1}=2.8

Therefore, mean of 1st row is 2.8.

\text{Mean of row 2}=\frac{3+3+4+3+2}{5}

\text{Mean of row 2}=\frac{15}{5}

\text{Mean of row 2}=3

Therefore, mean of 2nd row is 3.

\text{Mean of row 3}=\frac{2+4+3+4+3}{5}

\text{Mean of row 3}=\frac{16}{5}

\text{Mean of row 3}=3.2

Therefore, mean of 3rd row is 3.2.

\text{Mean of row 4}=\frac{3+4+4+7+3}{5}

\text{Mean of row 4}=\frac{21}{5}

\text{Mean of row 4}=4.2

Therefore, mean of 4th row is 4.2.

Since 4th row has the highest mean, therefore, 4th row will result in the greatest mean.

6 0
3 years ago
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Which is the standard form of the equation of the parabola that has a vertex of (3, 1) and a directric of x = -2?
vagabundo [1.1K]
Check the picture below.  So,the parabola looks like so, notice the distance "p". since the parabola is opening to the right, then "p" is positive, thus is 5.

\bf \textit{parabola vertex form with focus point distance}\\\\
\begin{array}{llll}
\boxed{(y-{{ k}})^2=4{{ p}}(x-{{ h}})} \\\\
(x-{{ h}})^2=4{{ p}}(y-{{ k}}) \\
\end{array}
\qquad 
\begin{array}{llll}
vertex\ ({{ h}},{{ k}})\\\\
{{ p}}=\textit{distance from vertex to }\\
\qquad \textit{ focus or directrix}
\end{array}\\\\

\bf -------------------------------\\\\
\begin{cases}
h=3\\
k=1\\
p=5
\end{cases}\implies (y-1)^2=4(5)(x-3)\implies (y-1)^2=20(x-3)
\\\\\\
\cfrac{1}{20}(y-1)^2=x-3\implies \boxed{\cfrac{1}{20}(y-1)^2+3=x}

8 0
3 years ago
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