Complete Question
Educational Television In a random sample of 200 people, 159 said that they watched educational television. Find the 90% confidence interval of the true proportion of people who watched educational television. Round the answers to at least three decimal places.
Answer:
The 90% confidence interval is
Step-by-step explanation:
From the question we are told that
The sample size is n = 200
The number of people that watched the educational television is 
Generally the sample proportion is mathematically represented as

=> 
From the question we are told the confidence level is 90% , hence the level of significance is
=>
Generally from the normal distribution table the critical value of
is
Generally the margin of error is mathematically represented as
=>
=>
Generally 95% confidence interval is mathematically represented as
=>
=>
Answer:
4
Step-by-step explanation:
2+2=4
Answer:
-7 and 7
Step-by-step explanation:
Hello,
8+h>2+3h
==>-2h>2-8
==>-2h>-6
==>h<3
Answer C
Answer:
y = -(2/3)m - 2
Step-by-step explanation:
recall that the general equation of a straight line in slope-intercept form is
y = mx + b
where, m is the slope and b is the y - intercept
here we are given that the y - intercept is -2, hence the equation becomes:
y = mx + (-2)
or
y = mx -2
we are also given that the x-intercept is -3, which means that when y = 0, x = -3 (simply substitute this into our new equation to solve for m)
0 = m(-3) -2
0 = -3m - 2 (add 3m to both sides)
3m = -2 (divide both sides by 3)
m = -(2/3)
hence our equation is now
y = -(2/3)m - 2