Answer:
6 thymine, 4 guanine. 4 cytosine
Explanation:
Adenine pairs with thymine, so you need 6 of each
Cytosine matches with guanine, but the total of nucleotides is 20, so
6(adenine)+6(thymine)=12
20-12=8
8= 4(guanine)+4(cytosine)
A mechanism that is effective in maintaining a normal glomerular blood pressure only if the systemic mean arterial pressure remains between 80 and 180 mm hg is called renal autoregulation.
<h3>What is renal autoregulation?</h3>
- Autoregulation is the inner characteristic of blood vessels present in end organs, like heart, kidney, and mind, by which they dilate or constrict in response to pressure changes, thus help to keep the blood flow generally steady.
- Usually our body tries to regulate our blood pressure in range of 50 to 150 mm Hg.
- Regulation of renal blood flow and glomerular blood pressure in kidneys is called renal autoregulation.
- There are 3 mechanisms of renal blood flow namely myogenic response (MR), tubuloglomerular feedback (TGF) and third mechanism that is independent of TGF but slower than MR.
Learn more about renal autoregulation here:
brainly.com/question/28064114
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Answer:
The correct answer will be-
1. decrease in blood volume
2. secretion of renin from juxtaglomerular apparatus
3. production of angiotensin II
4. secretion of aldosterone
5. sodium reabsorbed from distal tubules and collecting ducts
Explanation:
The RAAS pathway or Renin-angiotensin II-aldosterone pathway gets activated in the human body to maintain the osmolarity and blood volume.
When the receptors in the blood sense the low volume of water in the body sends signals to the brain which activates the secretion of the renin from the juxtaglomerular cells. Renin helps converts the inactive angiotensin to angiotensin I and II which help reabsorption of sodium ions. This activates the production of aldosterone which increases the reabsorption of the sodium ions into distal and collecting ducts.
The answer would be D.: <span>Helicases separate the two strands of the double helix, and DNA polymerases use each of the original strands as templates to create two new strands. :)</span>
