The height at time t is
h(t) = 144 - 16t²
When t = 0, then h = 144.
Therefore the height from the ground is 144 when the object is dropped.
When the object reaches the ground, h = 0.
Therefore
144 - 16t² = 0
t² = 144/16 = 9
t = 3 s
Answer:
The object reaches the ground in 3 seconds.
Step-by-step explanation:
2x-21+6=x-3
Answer:
2 sqrt(15)
Step-by-step explanation:
sqrt(60) = sqrt(4*15) = 2 sqrt(15)
Answer: 60, but I got other answers to but 60 was my first.
sorry if wrong.
Step-by-step explanation:
Answer:
y=-8
x=-23
Step-by-step explanation:
see attached document
