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3 years ago

2 lines are perpendicular and one line has a slope of 1/5 what is the slope of the other line

Mathematics

1 answer:

telo118 [61]3 years ago

6 0

Answer:

Slope: - 5

Step-by-step explanation:

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Rewrite each expression as a polynomial in standard form: x^2-5x+6 ÷ x-3 + x^3-1 ÷ x-1

iragen [17]

Answer:

So in standard form equation will be $x^2+2x-1$

Step-by-step explanation:

We have given expression $\frac{x^2-5x+6}{x-3}+\frac{x^3-1}{x-1}$

Let first we solve first part of the expression

So $\frac{x^2-5x+6}{x-3}=\frac{x^2-3x-2x+6}{x-3}=\frac{(x-3)(x-2)}{x-3}=x-2$

Now second part $\frac{x^3-1}{x-1}$

We know the algebraic identity $a^3-b^3=(a-b)(a^2+ab+b^2)$

So by using this identity

$\frac{x^3-1}{x-1}=\frac{(x-1)(x^2+x+1)}{x-1}=x^2+x+1$

Now adding first and second part

$x-2+x^2+x+1=x^2+2x-1$

So in standard form equation will be $x^2+2x-1$

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3 years ago

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Naya [18.7K]

Answer:

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2 years ago

Which property could be used to find the missing number?

LiRa [457]

–4 • (–6.2 + 5) = –4 • (-6.2) + (–4) • 5 it is the so called
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3 years ago

Which function is best represented by this graph

marishachu [46]

Answer:

y = -2x+4

Step-by-step explanation:

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1 year ago

(-2, 11) & (5,6) What is the slope of the equation between these two points?

ololo11 [35]

Answer:

$m =\dfrac{-5}{7}$

Step-by-step explanation:

Given :-

Two points (-2,11) and (5,6) .

And we need to find out the slope of the equation between the two points. The slope of the line passing through two points , is given by ,

$\implies Slope (m) =\dfrac{ y_2-y_1}{x_2-x_1}$

Here the two points are (-2,11) and (5,6) .So put on the respective values ,

$\implies Slope (m) =\dfrac{ 11 - 6}{-2-5}\\\\\implies Slope = \dfrac{5}{-7} \\\\\implies Slope = \dfrac{-5}{7}$

Hence the slope of the line is -5/7 .

8 0

2 years ago