Answer:
y-2 = -2(x+1)
Step-by-step explanation:
Find the slope(m) first using the two points (3, -6) and (-1, 2).
Slope: -2
Next, plug in x₁ and y₁. I plugged in (-1, 2)
Answer:
3/5
Step-by-step explanation:
Cos(B) = adjacent/hypotenuse
Cos(B) = 48/80 = 6/10
Cos(B) = 3/5 or 0.6
Given are the two points (-10,0) and (-8,20), and equation of the line as y=mx+b.
We can plug the given values in the equation as follows :-
0 = -10m + b .........equation(1)
20 = -8m + b .........equation(2)
Subtracting equation(1) from equation(2)
20 - 0 = (-8m + b) - (-10m + b)
20 = -8m + b + 10m - b
20 = 10m - 8m
20 = 2m
m = 10
Plugging m=10 in the equation(1)
0 = -10(10) + b
0 = -100 + b
b = 100
So final answer is b = 100.
Answer:
The intercepts of the third degree polynomial corresponds to the zeros of the equation
y = d*(x-a)*(x-b)(x-c)
Where a, b and c are the roots of the polynomial and d an adjustment coefficient.
y = d*(x+2)*(x)*(x-3)
Lets assume d = 1, and we get
y = (x+2)*(x)*(x-3) = x^3 - x^2 - 6x
We graph the equation in the attached file.
If the equation is y = 3(x + 4)2<span> - 6, the value of h is -4, and k is -6. To convert a quadratic from y = ax</span>2<span> + bx + c </span>form to vertex form, y = a(x - h)2+ k, you use the process of completing the square. Let's see an example. Convert y = 2x2<span> - 4x + 5 into </span>vertex form<span>, and state the </span>vertex<span>.</span>
