3 years ago

Find the oblique asymptote of f(x)= x+4/3x^2+5x-2

Mathematics

1 answer:

White raven [17]3 years ago

7 0

vertical asymptotes x = -2 , x

= 1 /3

horizontal asymptote y = 0

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What is the solution to this system of linear equations 2x+y=1 and 3x-y=-6

nikklg [1K]

2x + y = 1
3x - y = -6
---------------add
5x = -5
x = -5/5
x = -1

2(-1) + y = 1
-2 + y = 1
y = 1 + 2
y = 3

solution is (-1,3)

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3 years ago

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3 years ago

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Aloiza [94]

The equation of the line is y=6x+37

Step-by-step explanation:

You can write the equation using the slope intercept form techniques which is y=mx+c where m is the slope of the line and cis they intercept constant.

Given the point (-6,1) and slope m=6then

Δy/Δx =m

$y-1/x--6 = 6\\\\y-1/x+6=6\\\\\\y-1=6(x+6)\\\\\\y-1=6x+36\\\\\\y=6x+36+1\\\\y=6x+37$

5 0

3 years ago

Can someone simplify8x + 5x please

igor_vitrenko [27]

Answer:

13x

because you would comibne like terms, so you add the 8 and 5.

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3 years ago

Read 2 more answers

Three times the square of a nonzero number is equal to twelve times the number.

dedylja [7]

Well if you write the statement as an equation then that will get you

3*x^2 = 12x

Now we just solve. You can divide both sides by 3x and that gives you x = 4

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3 years ago