Answer:
mx + y = c slope = - 4 and y - intercept = 2 , then the equation of line is mx + y = c .
Step-by-step explanation:
If I am wrong sorry If I am right mark me brainliest
There are 13 clubs and 52 cards for a probability of 13/52= 1/4 for the first card being a club...
Answer:
Step-by-step explanation:
First, you gotta work out the hypotenuse of ABC, which is AC.
To do that, you need to figure out the scale factor between the two right-angled triangles. You can do that for this question because this is a similar shapes question.
12.5/5 = 2.5
The scale factor length between the two triangles is 2.5.
You can use 2.5 now to work out AC, so AC would be 13 x 2.5, which gives 32.5.
Now that you've got the hypotenuse and BC of ABC, you can use Pythagoras's theorem to work out the length of AB
Pythagoras's theorem = 
a = BC = 12.5
b = AB = we need to work this out
c = AC (the hypotenuse we just worked out) = 32.5
Let's both simplify and rearrange this at the same time so that we have our b on one side.
= 1056.25 - 156.25
b = 
b = 
b = AB = 30 We've found b or AB, now we can work out the perimeter of ABC.
Perimeter of ABC = AB + BC + AC
= 30 + 12.5 + 32.5
= 75 Here's the perimeter for ABC.
Answer:
CODE: 1977.98
Step-by-step explanation:
A.
(To get the closest answer, round the circumference to the nearest ten thousandth.)
C = 2(3.14)r Circumference formula: C = 2πr
C = 2(3.14)(3)
C = 18.84
B.
A = (3.14)r²
A = (3.14)(3)²
A = (3.14)(9)
A ≈ 28.26
C. (It's asking for the circumference.)
C = 2(3.14)r
C = 2(3.14)(58)
C ≈ 364.24
D. (It's a linear pair, which is 180 degrees.)
4x + 2x = 180
6x = 180
x = 30
m∠ABD = 4x
m∠ABD = 4(30)
m∠ABD = 120°
E. (∠GHI & ∠JHK are vertical angles, so they are congruent.)
x + 7 = 3x - 21
28 = 2x
14 = x
F. (x = 14)
m∠JHK = 3x - 21
m∠JHK = 3(14) - 21
m∠JHK = 42 - 21
m∠JHK = 21°
G. (Supplementary - two angles that add up to 180 degrees.)
180 - 84
= 96°
CODE: E(C - D) - F(G - B) - A
CODE: 14(364.24 - 120) - 21(96 - 28.26) - 18.84
CODE: 14(244.24) - 21(67.74) - 18.84
CODE: 3419.36 - 1422.54 - 18.84
CODE: 1977.98
Quadrant II.
Hope this helps.
