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Bingel [31]
2 years ago
11

Alan bought 20 yards of fencing. he used 5.9 yards to surround one flower garden and 10.3 yards to surround another garden.write

the amount remaining as a fraction in simplest form.
Mathematics
2 answers:
marusya05 [52]2 years ago
8 0
The answer for this question is that the remaining amount fencing left after Alan has completed his garden will be 3 4/5 yards. This can be worked out, by first determining that the overall amount of fencing Alan used was 5.9 + 10.3, to create a total of 16.2. The remaining amount of fence can therefore be calculated by subtracting 16.2 from 20 to get 3.8 yeards. As a fraction this would then by written as 3 8/10, which can then be simplified down to get your answer of 3 4/5.
Paladinen [302]2 years ago
4 0

<u>step 1</u>

<u>Determine the total amount of fencing used by Alan</u>

5.9+10.3=16.2\ yards

<u>step 2</u>

<u>Determine the remaining amount of fence</u>

Subtract 16.2 from 20

20-16.2=3.8\ yards

<u>step 3</u>

<u>convert the amount remaining as a fraction in simplest form</u>

3.8= 3+0.8 =3+\frac{8}{10} = 3\frac{4}{5} \ yards

therefore

<u>the answer is</u>

3\frac{4}{5} \ yards


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Beta= 1.3

Debt to equity ratio= 0.4

Market rate of return= 11.6%

= 11.6/100

= 0.116

Tax rate= 32%

= 32/100

= 0.32

Risk free rate=  3.3%

= 3.3/100

= 0.033

Pretax cost of debt= 7.2%

= 7.2/100

= 0.072

The firm's WACC can be calacluated as follows

RS= 0.033+1.3(0.116-0.033)

= 0.033+1.3(0.083)

= 0.033+0.1079

= 0.1409

WACC= (1/1.4)(0.1409)+(2/1.4) (0.072)(1-0.32)

= (0.7142)(0.1409) + (1.4285)(0.072)(0.68)

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6 0
2 years ago
Find the center and radius of this circle x^2+y^2-6x-10y+30=0
Vsevolod [243]

Answer:

The circle's centre is at the position (3, 5), and it has a radius of 2

Step-by-step explanation:

First let's put it in a useful format by completing the squares:

x² + y² - 6x - 10y + 30 = 0

x² - 6x + y² - 10y = -30

x² - 6x + 9 + y² - 10y + 25 = -30 + 9 + 25

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5 0
2 years ago
Find the midsegment of triangle ABC so that it is parallel to side BC and label it as segment EG on the graph.
Lelechka [254]

Answer:

Coordinate of E:(-2,3) Coordinate of G: (2.5,1.5)

Parallel: slopes both = -1/3

1/2 segment: EG length= 3 BC length=6: This is the only one I'm not sure about.

I will show the work for both the problems down below.

Step-by-step explanation:

Finding coordinates:

1+(-5)/2=-2  5+1/2=3

(-2,3)

1+4/2= 2.5   5+(-2)/2= 1.5

(2.5,1.5)

Show work verifying the EG and BC are parallel:

You can do this by finding the slope

Slop formula (y2-y1)/(x2-x1)

(1.5-3)/(2.5-(-2))

Then simplify

-1.5/2/5= -1/3 which i your slope. You use the same formula and follow thee same steps for the points of BC and both will come up as -1/4 meaning they are parallel.

Show work verifying that EG and BC are parallel:

Use distance formula to find how long each line is

√(x2-x1)^2+(y2-y1)^2

√(2.5-(-2)^2)+(1.5-3)^2

Simplify

√4.5+(1.5)=3

Do the same thing with BC and you will get 6






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3 years ago
Pre Calc Question Help,
julsineya [31]

Answer:

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Domain is the set of all values of x where the function is defined. For this function the only limitation upon x exists when the denominator would equal zero, because division by zero is undefined. So the denominator 13-x cannot equal zero thus x cannot equal 13. Thus the domain is all real numbers except 13.

5 0
3 years ago
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