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2 years ago

PLEASE HELP THANKS.

Mathematics

2 answers:

sergiy2304 [10]2 years ago

8 0

Answer:

23283.33 foot

Step-by-step explanation:

Tan θ = Perpendicular Base

=> Tanθ = 15000/25000

=> Tanθ = 3/5

=> Tanθ = 0.6

=> θ = 30.96°

Tan(θ + 12) = H/25000

=> H = 25000 * Tan(θ + 12)

Tan(θ + 12) = Tan(30.96° + 12)

=> Tan(θ + 12) = Tan(42.96°)

=> Tan(θ + 12) = 0.931333

=> H = 25000 * 0.931333

=> H = 23283.33

the altitude of the rocket at 10:02 am to the nearest tenth of a foot = 23283.33 foot

Now can you mark me brainliest please?

Schach [20]2 years ago

4 0

Answer:

23283.33 foot

Step-by-step explanation:

Tan θ = Perpendicular Base

=> Tanθ = 15000/25000

=> Tanθ = 3/5

=> Tanθ = 0.6

=> θ = 30.96°

Tan(θ + 12) = H/25000

=> H = 25000 * Tan(θ + 12)

Tan(θ + 12) = Tan(30.96° + 12)

=> Tan(θ + 12) = Tan(42.96°)

=> Tan(θ + 12) = 0.931333

=> H = 25000 * 0.931333

=> H = 23283.33

the altitude of the rocket at 10:02 am to the nearest tenth of a foot = 23283.33 foot

Now you can give ''nooris0663'' brainliest. :)

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