2 answers:
Answer:
23283.33 foot
Step-by-step explanation:
Tan θ = Perpendicular Base
=> Tanθ = 15000/25000
=> Tanθ = 3/5
=> Tanθ = 0.6
=> θ = 30.96°
Tan(θ + 12) = H/25000
=> H = 25000 * Tan(θ + 12)
Tan(θ + 12) = Tan(30.96° + 12)
=> Tan(θ + 12) = Tan(42.96°)
=> Tan(θ + 12) = 0.931333
=> H = 25000 * 0.931333
=> H = 23283.33
the altitude of the rocket at 10:02 am to the nearest tenth of a foot = 23283.33 foot
Now can you mark me brainliest please?
Answer:
23283.33 foot
Step-by-step explanation:
Tan θ = Perpendicular Base
=> Tanθ = 15000/25000
=> Tanθ = 3/5
=> Tanθ = 0.6
=> θ = 30.96°
Tan(θ + 12) = H/25000
=> H = 25000 * Tan(θ + 12)
Tan(θ + 12) = Tan(30.96° + 12)
=> Tan(θ + 12) = Tan(42.96°)
=> Tan(θ + 12) = 0.931333
=> H = 25000 * 0.931333
=> H = 23283.33
the altitude of the rocket at 10:02 am to the nearest tenth of a foot = 23283.33 foot
Now you can give ''nooris0663'' brainliest. :)
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