Question

PLEASE HELP THANKS.

Answer 1

Answer:

23283.33  foot

Step-by-step explanation:

Tan θ = Perpendicular Base

=> Tanθ = 15000/25000

=> Tanθ = 3/5

=> Tanθ = 0.6

=> θ = 30.96°

Tan(θ + 12) = H/25000

=> H = 25000 * Tan(θ + 12)

Tan(θ + 12) =  Tan(30.96° + 12)

=> Tan(θ + 12) =  Tan(42.96°)

=>  Tan(θ + 12) = 0.931333

=> H = 25000 * 0.931333

=> H = 23283.33

the altitude of the rocket at 10:02 am to the nearest tenth of a foot = 23283.33  foot

Now can you mark me brainliest please?

Answer 2

Answer:

23283.33  foot

Step-by-step explanation:

Tan θ = Perpendicular Base

=> Tanθ = 15000/25000

=> Tanθ = 3/5

=> Tanθ = 0.6

=> θ = 30.96°

Tan(θ + 12) = H/25000

=> H = 25000 * Tan(θ + 12)

Tan(θ + 12) =  Tan(30.96° + 12)

=> Tan(θ + 12) =  Tan(42.96°)

=>  Tan(θ + 12) = 0.931333

=> H = 25000 * 0.931333

=> H = 23283.33

the altitude of the rocket at 10:02 am to the nearest tenth of a foot = 23283.33  foot

Now you can give ''nooris0663'' brainliest. :)