You need to prove that <A = <E
since c is the midpoint of line AE then AC = EC
i dont remember the name of the theroem that states that when a triangle has two sides and an angle in common that it is congruent i think it called SAS congruence therom. use that to prove that the <| s are congruent then use CPCTC to prove that <A = <E. then prove that they are || by usint the int angle therom.
First, divide both sides by 3. I think your mistake was that you were multiplying -3. Please note that in order to cancel something out you need to do the reverse operation. The reverse operation of subtraction is addition and the reverse of multiplication is division.
3(a - 5) = -6
a - 5 = -2
Now add 5 to both sides
a - 5 = -2
+5 +5
a = 3
Hope this helps!
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what grade is this???
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026.71 seconds
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h=0.46^2