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Slav-nsk [51]
3 years ago
11

In which quadrant is the number 6 – 8i located on the complex plane?

Mathematics
2 answers:
ivolga24 [154]3 years ago
5 0

Answer: The given complex number 6-8i will be located in fourth quadrant

Explanation:

We have a coordinate plane and which consists of four quadrants

In first quadrant both the coordinates (x,y) are positive can be represented as (+,+)

In second quadrant x-axis will be negative and y-axis will be positive and represented as (-,+)

In third quadrant both the coordinates will be negative and represented as (-,-)

In fourth quadrant x-axis will be positive and y-axis will be negative and represented as (+,-)

Our required complex number will lie in fourth quadrant since, its x-axis is positive and y-axis is negative.

antoniya [11.8K]3 years ago
4 0
<span>The number 6 – 8i is located in the 4th quadrant </span><span>on the complex plane.</span>
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Step-by-step explanation:

This seems to be calculus 1.

<u>Question a</u>

We have -2x^3 + 5x^2 + 9

m = slope = derivative

Find the derivative / slope of -2x^3 + 5x^2 + 9

We do this by differentiating the polynomials. There are a few methods to do this but I am going to use the power rule, which we multiply the constant by the exponent on the variable and subtract one from the exponent.

\frac{d}{dx}(-2x^3 + 5x^2 + 9)

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<em>Now that we have this information, we can answer question b</em>

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<u>The tangent line for Point (1, 12)</u>

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<u>Now lets do the same for the Point (2, 13)</u>

Find the slope at the point.

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Now graph the lines, which I have done and you can see by viewing the image I have attached.


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3 years ago
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