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3 years ago

In the electron transport system, hydrogen atoms removed from NADH ultimately end up as part of _____

Chemistry

1 answer:

erica [24]3 years ago

5 0

Answer: Water H2O

Explanation:

In cellular respiration process NAD+ is a most versatile electron acceptor and functions in several of the redox steps during break down of glucose.

Each NADH molecules formed during respiration represents stored energy that can be tapped to make ATP when the electrons complete their ''fall''down an energy gradient from NADH to oxygen.

Electrons removed from glucose are shuttle by NADH to the ''top'', higher-energy end of the electron transport chain. At the ''bottom'' lower energy end, O2 captures these electrons along with H+ forming water.

Therefore Hydrogen removed from NADH in the ETC is captured by O2 to form water

2H + 1/2O2 ------> H20

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2 years ago

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2 years ago

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Answer:

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2 years ago

Uranium-238 decays to lead-206 with a half-life of 4.5 x 109 yr. Determine how much uranium-238 decays in milligrams (to three s

Mamont248 [21]

Answer:

2.15 mg of uranium-238 decays

Explanation:

For decay of radioactive nuclide-

$N=N_{0}.(\frac{1}{2})^{\frac{t}{t_{\frac{1}{2}}}}$

where N is amount of radioactive nuclide after t time, $N_{0}$ is initial amount of radioactive nuclide and $t_{\frac{1}{2}}$ is half life of radioactive nuclide

Here $N_{0}=4.60 mg$ , $t=4.1\times 10^{9}yr$ and $t_{\frac{1}{2}}=4.5\times 10^{9}yr$

So, $N=(4.60mg)\times (\frac{1}{2})^{\frac{4.1\times 10^{9}}{4.5\times 10^{9}}}$

so, N = 2.446 mg

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2 years ago

In the synthesis reaction, the white powder produced is magnesium oxide (mgo, mm = 40.3 g/mol). how many moles of magnesium oxid

gulaghasi [49]

Number of moles = mass of product / molecular mass
=mass of product (MgO) / 40.3

Since the mass of MgO is not given in the question, the correct answer choice cannot be given. However, proceeding witht eh above formula will enable you to find the correct number of moles given the mass of MgO.

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2 years ago