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mr_godi [17]
3 years ago
8

What is the limit of

+2x^2" alt="\sf f(x)=3x^3+2x^2" align="absmiddle" class="latex-formula"> as \sf x approaches \sf 5?
Mathematics
2 answers:
anastassius [24]3 years ago
8 0

Answer:

just plug 5 into the (x) that's all

PtichkaEL [24]3 years ago
3 0

Answer:

Giới hạn của [tex] \ sf f (x) = 3x ^ 3 + 2x ^ 2 [/ tex] khi [tex] \ sf x [/ tex] tiếp cận [tex] \ sf 5 [/ tex]?

Step-by-step explanation:

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inysia [295]

Answer:

x=-1

Step-by-step explanation:

2x+6=3-x

Step 1: Simplify both sides of the equation.

2x+6=3−x

2x+6=3+(−x)

2x+6=−x+3

Step 2: Add x to both sides.

2x+6+x=−x+3+x

3x+6=3

Step 3: Subtract 6 from both sides.

3x+6−6=3−6

3x=−3

Step 4: Divide both sides by 3.

3x/3=−3/3

x=−1

Answer:

x=−1

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Step-by-step explanation:

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