Ask question

Ask question

All categories

3 years ago

6

Please help me i dont want to fail

1 answer:

Julli [10]3 years ago

5 0

Answer:

sorrry pooooo need ko lang po ng points

You might be interested in

A women has 157.5 different ribbons. How many different ribbons does she have?

kykrilka [37]

Answer:

158 ribbons even half of one still counts.

Step-by-step explanation:

7 0

3 years ago

Help me out homies please

Romashka [77]

So he knows there are definitely 66 trouts as he caught and tagged them.
The next day he caught 52, but 13 of them were already tagged, so were part of the number of trout he caught before.
So he can expect that:
66+(52-13)= 105 trout are in the lake

3 0

3 years ago

A restaurant owner is interested in the proportion of his customers who order dessert. He looks at 65 randomly selected receipts

xxTIMURxx [149]

Answer:

c. Population

Step-by-step explanation:

All customers who come to the restaurant are the population.

The 65 randomly selected customers are the sample.

The correct answer is:

c. Population

4 0

4 years ago

The length of a rectangle is 8 centimeters. what is the width?

topjm [15]

Answer:

This is a very vague question. We can't find out the width if it doesn't tell us the area. Comment on my answer the area and I can help.

7 0

3 years ago

: A new bear population that begins with 150 bears in 2000 decreases at a rate of 20% per year.

d1i1m1o1n [39]

Answer:

2 bears in 2020.

Step-by-step explanation:

We have been given that a new bear population that begins with 150 bears in 2000 decreases at a rate of 20% per year.

We will use exponential decay formula to solve our given problem as:

$y=a\cdot (1-r)^x$ , where,

y = Final quantity,

a = Initial value,

r = Decay rate in decimal form,

x = Time

$20\%=\frac{20}{100}=0.20$

Upon substituting our given values in above formula, we will get:

$y=150(1-0.20)^x$

$y=150(0.80)^x$ , where x corresponds to year 2000.

To find the population in 2020, we will substitute $x=20$ in our equation as:

$y=150(0.80)^{20}$

$y=150(0.011529215046)$

$y=1.7293822569$

$y\approx 2$

Therefore, 2 bears are there predicted to be in 2020.

Since population is decreasing so population is best described as exponential decay.

8 0

3 years ago