At a package weight of 8 they both cost $37
Answer:
The probability that at least 1 car arrives during the call is 0.9306
Step-by-step explanation:
Cars arriving according to Poisson process - 80 Cars per hour
If the attendant makes a 2 minute phone call, then effective λ = 80/60 * 2 = 2.66666667 = 2.67 X ≅ Poisson (λ = 2.67)
Now, we find the probability: P(X≥1)
P(X≥1) = 1 - p(x < 1)
P(X≥1) = 1 - p(x=0)
P(X≥1) = 1 - [ (e^-λ) * λ^0] / 0!
P(X≥1) = 1 - e^-2.67
P(X≥1) = 1 - 0.06945
P(X≥1) = 0.93055
P(X≥1) = 0.9306
Thus, the probability that at least 1 car arrives during the call is 0.9306.
Answer:
the square root of 75 is either 
or 8.66
Step-by-step explanation:
Answer:
x=7
Step-by-step explanation:
AC=3x+3 AB=-1+2x and BC=11
AC = AB + BC
ALL THE STEPS:
3 X + 3 = - 1 + 2 X + 11
3 X + 3 = 2 X + 10
3 X + ( - 2 X ) + 3 = 2 X + ( - 2 X ) + 10
X + 3 = 10
X + 3 + ( - 3 ) = 10 + ( - 3 )
X = 7
It’s the first one. I think
