we have
x=5−2y ---> multiply by 3 both sides-----> 3x=15-6y-----> 6y=15-3x----> equation 1
6y=10−3x------> equation 2
equation 1 and equation 2 has the same slope
the lines are parallel
slope m=-3/6-----> m=-1/2
so
there are no solution
the answer is the option
b. There is no solution
Move the negative sign to the left
-x/5 = -20
Multiply both sides by 5
-x = -20 × 5
Simplify 20 × 5 to 100
-x = -100
Multiply both sides by -1
<em>x = 100</em>
<u>C. 100</u>
Answer:
y = 1/6 x^2 + 8/3 x + 49/6
Step-by-step explanation:
This is a parabola which opens upwards.
The distance of a point (x, y) from the focus is
√[(x - -8)^2 + (y - -1)^2] and
the distance of the point from the line y = -4
= y - -4
These distances are equal for a parabola so:
√[(x - -8)^2 + (y - -1)^2] = y + 4
Squaring both sides:
(x + 8)^2 + (y + 1)^2 = (y + 4)^2
x^2 + 16x + 64 + y^2 + 2y + 1 = y^2 + 8y + 16
x^2 + 16x + 64 + 1 - 16 = 8y - 2y
6y = x^2 + 16x + 49
y = 1/6 x^2 + 8/3 x + 49/6 is the equation of the parabola.
Answer:
<h3>The value C(t) of the car after 5 years is $12709.</h3>
Step-by-step explanation:
Given that Landon bought a new car for $16,000 and it depreciates 4.5% every year.
<h3>To find the value C(t) of the car after 5 years:</h3>
Initial value 
Depreciation rate is 
<h3>∴ r=0.045</h3>
Period , t=5 years

Substitute the values we get



∴ 
<h3>The value C(t) of the car after 5 years is $
12709</h3>
Answer:
Denote AH as height of triangle ABC, with H lies on BC.
Applying sine theorem:
AH/AC = sin 60
=> AH = AC x sin 60 = 47 x sqrt(3)/2 = 40.7
=> Area of triangle ABC is calculated by:
A = AH x BC x (1/2) = 40.7 x 30 x (1/2) = 610.5 = ~611
=> Option C is correct.
Hope this helps!
:)