For this case we have the following expression:
We eliminate the parentheses taking into account that:
We add similar terms:
Different signs are subtracted and the sign of the major is placed:
Finally, the expression is reduced to:
Answer:
Option B
Find the value of x that will make A||B
2 answers:
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Answer:
Step-by-step explanation:
The average cost for the training session provided he is a sports trainer can be computed as follows:
Let's assume that;
average cost = C(x)
the no. of session = x
Then:
Now, suppose the trainer wants the average cost C(x) to drop below $16;
Then, we have the following function:
By cross multiply:
120 + 15x ≤ 16x
120 ≤ 16x - 15x
120 ≤ x
Therefore, the required no. of session, if the average cost should drop below $16, is 120.
Answer:
For school A: Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17, IQR=9.5
For school B: Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19, IQR=7.5
No, the box plots are not symmetric.
Step-by-step explanation:
Part A
The given data sets are
School A : 9,14,15,17,17,7,15,6,6
School B : 12,8,13,11,19,15,16,5,8
Arrange the data in ascending order.
School A : 6,6,7,9,14,15,15,17,17
School B : 5,8,8,11,12,13,15,16,19
Divide each data set in four equal parts.
School A : (6,6),(7,9),14,(15,15),(17,17)
School B : (5,8),(8,11),12,(13,15),(16,19)
For school A:
Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17
Interquartile range of the data is
For school B:
Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19
Interquartile range of the data is
Part B:
The box plots are not symmetric because the data values are different. Five number summary and IQR of both the data set are different.