3 years ago

Need help due tmr pls!!b!!!!

Mathematics

1 answer:

8090 [49]3 years ago

5 0

Please supload it again it’s black

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Answer:

(a) $h(t)=\frac{1.3t^2}{2} + 2t +17$

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The growth rate of the shrub is given as:

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$\int \frac{dh}{dt} dt= \int (1.3t + 2)dt\\h(t)=\frac{1.3t^2}{2} + 2t +C, $ C a constant of Integration$\\$We sunstitute the initial value to find the value of C$\\$When t=0, h=17cm$\\17=C\\Therefore:\\h(t)=\frac{1.3t^2}{2} + 2t +17$

(b)The shrub are sold after 7 years of growth. Therefore, we determine the value of h(t) when t=7 years.

$h(t)=\frac{1.3t^2}{2} + 2t +17\\h(7)=\frac{1.3*7^2}{2} + 2(7) +17\\=31.85+14+17\\h(7)=62.85cm$

The Shrubs are 62.85cm tall when they are sold.

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