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2 years ago

How many more points do I need for a gpa of a 2.0

Mathematics

2 answers:

madreJ [45]2 years ago

8 0

Answer:

you need at least a score of 60

Step-by-step explanation:

anything 59 and below is 1.95 and every percent higher it adds .5 more

NISA [10]2 years ago

7 0

Answer:

Letter Grade: C -

Percent Grade: 73 -76

GPA: 2.0

Step-by-step explanation:

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Simplify expression x8y-26/x14y-5 × x-39y-21

koban [17]

The simplified form of the expression is $x^{-45} y^{-42}$

<h3>Simplifying an expression</h3>

From the question, we are to simplify the given expression

The given expression is

$\frac{x^{8}y^{-26} }{x^{14}y^{-5} } \times x^{-39} y^{-21}$

The expression can be simplified as shown below

$\frac{x^{8}y^{-26} }{x^{14}y^{-5} } \times x^{-39} y^{-21}$

$\frac{x^{8} \times x^{-39} \times y^{-26} \times y^{-21} }{x^{14} \times y^{-5} }$

$\frac{x^{8+-39} \times y^{-26+-21} }{x^{14} \times y^{-5} }$

$\frac{x^{8-39} \times y^{-26-21} }{x^{14} \times y^{-5} }$

$\frac{x^{-31} \times y^{-47} }{x^{14} \times y^{-5} }$

Then,

$\frac{x^{-31} }{x^{14} } \times \frac{ y^{-47} }{ y^{-5} }$

$x^{-31-14} \times y^{-47--5}$

$x^{-31-14} \times y^{-47+5}$

$x^{-45} \times y^{-42}$

$x^{-45} y^{-42}$

Hence, the simplified form of the expression is $x^{-45} y^{-42}$

Learn more on Simplifying an expression here: brainly.com/question/2320607

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2 years ago

PLZ HELP ME!!!!!!!!!!!!!! 20 pOINTS

Bad White [126]

Answer:

Step-by-step explanation:

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2 years ago

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55x^ 2 + 62y^ 2 + 38 − 63x^ 2 + 8

worty [1.4K]

What are you trying to do like simplify or what i can possibly help if i know

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As a Given the function f(x) = - 3x + 2 then what is - 2f * (x) as a simplified polynomial ?

Lady bird [3.3K]

Answer: 6x - 4

Step-by-step explanation: -2*f(x) = -2 * (-3x+2) = (-2*-3x) + (-2*2) = 6x + (-4) = 6x - 4

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2 years ago

I NEED THE ANSWER NOWWWWWWWWWWWWWW

Verizon [17]

Answer:

I think it might be $123.75

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3 years ago

How many more points do I need for a gpa of a 2.0​

How many more points do I need for a gpa of a 2.0