Let <em>x</em> be the smallest of the three integers. Then the next two are <em>x</em> + 2 and <em>x</em> + 4.
• "The ratio of the smallest number to 1 less than twice the smallest number..."
This translates to
<em>x</em> / (2<em>x</em> - 1)
• "... the ratio of 3 more than the middle number to twice the largest number."
This translates to
((<em>x</em> + 2) + 3) / (2 (<em>x</em> + 4))
or, simplifying a bit,
(<em>x</em> + 5) / (2<em>x</em> + 8)
The ratioes are said to be equivalent, so
<em>x</em> / (2<em>x</em> - 1) = (<em>x</em> + 5) / (2<em>x</em> + 8)
Solve for <em>x</em> :
<em>x</em> (2<em>x</em> + 8) = (<em>x</em> + 5) (2<em>x</em> - 1)
2<em>x</em>² + 8<em>x</em> = 2<em>x</em>² + 9<em>x</em> - 5
8<em>x</em> = 9<em>x</em> - 5
-<em>x</em> = -5
<em>x</em> = 5
So the three integers are 5, 7, and 9.
Answer: =7y^2+20y−3
Step-by-step explanation:
When you look at the x = 0 and y = -2, that is the y-intercept since the x = 0.
Then when you look at the second one, it goes right one and up four.
As rise over run, it would be 4 / 1 or simply 4.
The slope is 4 and the y-intercept is -2
Plug it in the equation: y = mx + b. M is the slope and B is the y-intercept.
y = 4x -2
The interquartile range is 1.5
Q1 = 38 (between 34 and 43)
Median = 39
Q3 = 39.5 (between 39 and 40)
To get the interquartile range you find the difference with Q3 and Q1
39.5 - 38 = 1.5
