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Dmitriy789 [7]
3 years ago
9

A carnival charges a $5 admission fee plus $1 per ride. Find the cost of 6 rides

Mathematics
2 answers:
Ad libitum [116K]3 years ago
8 0
Including the admission fee and 6 rides, the cost would be $11. $5×(+)6×$1=11
Harrizon [31]3 years ago
7 0
Set up a problem: $5 is a one time thing but $1 is once for each of the 6 rides: 5+(1•6)=X. Multiply: 1•6=6. Add: 5+6=11. $5+$1•6=$11 :)
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(03.08A)
DiKsa [7]

Answer:

4 + (-5)

Step-by-step explanation:

4 - 5 = 4 + (-5) = -1

Additive inverse of 5 = (-5)

6 0
2 years ago
Find the distance between the points (-8,-11) and (14,-11).​
coldgirl [10]

Answer:

Distance =(x2−x1)2+(y2−y1)2−−−−−−−−−−−−−−−−−−√

Step-by-step explanation:

The answer is provided above.

Distance =(x2−x1)2+(y2−y1)2−−−−−−−−−−−−−−−−−−√

Hope this helps.

6 0
3 years ago
Read 2 more answers
Someone please help me answer this!!
astra-53 [7]

Answer:

c = 53 miles

Step-by-step explanation:

a^2 + b^2 = c^2

45^2 + 28^2 = c^2

2,025 + 784 = c^2

2809 = c^2

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3 0
3 years ago
Juice: 48 fluid ounces for $2.07; 32 fluid ounces for $1.64
Alla [95]

Answer:

Step-by-step explanation:

Start by changing the dollars into cents.

2.07 dollars = 2.07 * 100 = 207 cents

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The better buy is the 48 fluid oz jar.

5 0
2 years ago
Match each of the parametric equations 1-5 with the curve it represents from the list A through E below. 1. r=3 2. r=2sinθ 3. θ=
ira [324]

Answer:

Step-by-step explanation:

1. r=3

To convert from polar coordinates (r,θ) to rectangular coordinates (x,y), we use the following equations

x=rCosθ

Cosθ=x/r

y=rSinθ

Sinθ=y/r

Also, r²=x²+y²

When r =3,

Then we have

r=3,

x²+y²=3

All points with r = 3 are at

distance 3 from the origin, so r = 3 describes the circle of radius 3, with center at the origin (0,0).

Option C

2. r=2sinθ

When r=2sinθ

To convert from polar coordinates (r,θ) to rectangular coordinates (x,y), we use the following equations

x=rCosθ

Cosθ=x/r

y=rSinθ

Sinθ=y/r

Also, r²=x²+y²

Now, apply the given information

r=2sinθ

Since Sinθ=y/r

r=2y/r

Cross multiply

r²=2y

x²+y²=2y

x²+y²-2y =0

x²+ (y-1)² -1 =0

x²+(y-1)²=1²

Then,

It is a circle with center (0,1) and radius 1.

Because the sine is periodic, we know that we will get the entire curve for values of θ in [0, 2π). As θ runs from 0 to π/2, r increases

from 0 to 2. Then as θ continues to π, r decreases again to 0. When θ runs from π to

2π, r is negative, and it is not hard to see that the first part of the curve is simply traced

out again, so in fact we get the whole curve for values of θ in [0, π). Thus, check attachment for curve, Now, this suggests that the curve could possibly be a circle,

and if it is, it would have to be the circle x² + (y − 1)² = 1. Having made this guess, we can easily check it. First we substitute for x and y to get (r cos θ)² + (r sin θ − 1)² = 1;

expanding and simplifying does indeed turn this into r = 2 sin θ.

Option E

A circle of radius 1 with center on the x-axis

3. θ=π/4

This is a point on the circle

p=(r, θ)

So, r=0

x = rCosπ/4=rCos45

x=r√2 /2

and

y = rsin(π/4) = rSin45

y=r√2 /2

This makes it very

easy to convert equations from rectangular to polar coordinates.

x²+y²= (r√2/2)²+(r√2/2)²

x²+y²= 2r²/4 + 2r²/4

x²+y²= r²

Since r=0

x²+y²= 0

x²=y²

Therefore, x=y

Option D

The straight line y=x

4. r=4θ

Here the distance from the origin

exactly matches the angle, so a bit of thought makes it clear that when θ ≥ 0 we get the spiral of Archimedes ( check attachment ) When θ < 0, r is also negative, and so the full graph is the right hand picture in the figure. Check attachment

The correct option is B

None of the above

5. r=2Cosθ

To convert from polar coordinates (r,θ) to rectangular coordinates (x,y), we use the following equations

x=rCosθ

Cosθ=x/r

y=rSinθ

Sinθ=y/r

Also, r²=x²+y²

Now, apply the given information

r=2cosθ

Since cosθ=x/r

r=2x/r

Cross multiply

r²=2x

x²+y²=2x

x²+y²-2x=0

(x-1)² + y² -1 =0

(x-1)² + y² = 1²

Then,

It is a circle with center (1,0) and radius 1.

A circle of radius 1 with center on the y-axis

Option A is correct

7 0
3 years ago
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