Let the width = x
=>length = 2x-1
91= x(2x-1)=2x^2-x
2x^2-x-91=0
=(2x+13)(x-7)
=> x=-13/2=> no
=>x= 7 cm
Answer: y=66
I hope it helps you!
Answer:
D
Step-by-step explanation:
A)
3(2) + 4(-2) = -2 2(2)-4(-2) = -8
6 - 8 = -2 4 + 8 = -8
Correct Incorrect
B)
3(6) + 4(-5) = -2 2(6) - 4(-5) = -8
18 - 20 = -2 12 + 20 = -8
Correct incorrect
C)
3(4) + 4(4) = -2
12 + 8 = -2
incorrect
D)
3(-2) + 4(1) =-2 2(-2) - 4(1) = -8
-6 + 4 = -2 -4 - 4 = -8
Correct Correct
Best way is process of elimination
Answer:
none of them
Step-by-step explanation:
Two lines are perpendicular when satisfy the next equation: m1*m2 = -1, where m1 and m2 are the slopes o the lines.
line 1:
y – 1 = (x+2)
y = x + 3
slope of line 1 = 1
line 2:
y + 2 = –3(x – 4)
y + 2 =
-3*x + 12
y = -3*x + 10
slope of line 2 = -3
m1*m2 = 1*(-3
) = -3
They are not perpendicular
line 3:
y − 5 = 3(x + 11)
y − 5 = 3*x + 33
y = 3*x + 38
slope of line 3 = 3
m1*m3 = 1*3 = 3
They are not perpendicular
line 4:
y = -3x –
slope of line 4 = -3
m1*m4 = 1*(-3
) = -3
They are not perpendicular
line 5:
y = x – 2
slope of line 5 = 1
m1*m5 = 1*1 = 1
They are not perpendicular
line 6:
3x + y = 7
y = -3x + 7
slope of line 6 = -3
m1*m6 = 1*(-3
) = -3
They are not perpendicular
