Answer:
y = x/2 - 7
Step-by-step explanation:
First, we need to find the slope of the given equation: x - 2y = 8
Subtract x from both sides
x - 2y = 8
- x - x
-2y = 8 - x
Divide both sides by -2
-2y/-2 = (8 - x)/-2
y = -4 + x/2
The slope of this equation is 1/2
So the equation of our parallel equation is y = x/2 + b
We have to find b, so plug in the given coordinates
-6 = 2/2 + b
-6 = 1 + b
Subtract 1 from both sides
-6 = 1 + b
- 1 - 1
b = -7
Plug it back into the original equation
y = x/2 - 7
Answer:
12,39,21,18,24,17,12,25
Step-by-step explanation:
First row, the answer on the left , -5 3/4 - 4 2/3
Answer
In decimal form it is 1.25 and in fraction form it 1/4
Step-by-step explanation:
There might be and there are other ways but the way I did it is I converted the fractions to decimals. 1 3/4= 1.75, 1 1/2= 1.5, and 4 1/2 equals 4.5. So I added the time he practiced on Monday and Tuesday and subtracted it from the final hour of the whole entire week and the answer is 1.25 or 1/4
Answer:
yes
Step-by-step explanation:
The line intersects each parabola in one point, so is tangent to both.
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For the first parabola, the point of intersection is ...
y^2 = 4(-y-1)
y^2 +4y +4 = 0
(y+2)^2 = 0
y = -2 . . . . . . . . one solution only
x = -(-2)-1 = 1
The point of intersection is (1, -2).
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For the second parabola, the equation is the same, but with x and y interchanged:
x^2 = 4(-x-1)
(x +2)^2 = 0
x = -2, y = 1 . . . . . one point of intersection only
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If the line is not parallel to the axis of symmetry, it is tangent if there is only one point of intersection. Here the line x+y+1=0 is tangent to both y^2=4x and x^2=4y.
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Another way to consider this is to look at the two parabolas as mirror images of each other across the line y=x. The given line is perpendicular to that line of reflection, so if it is tangent to one parabola, it is tangent to both.