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Igoryamba
3 years ago
10

((2.0265-2.02)/2.0265) x 100.00

Chemistry
1 answer:
lianna [129]3 years ago
3 0

Answer 0.5

when reporting calculations from sig figs, report the number of sig figs in the least accurate measurement

so

((2.0265-2.02)/2.0265) x 100.00

((2.0265/2.0265) - (2.02/2.03)) X 100.00

(1.0000 -0.995) X 100.00

0.005 X 100.00

0.5

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Mass box A = 10 grams; Mass box B = 5 grams; Mass box C—made of one A and one B How many boxes of B would be required to make 30
Iteru [2.4K]
Mass box C is 10+5. (So C is 15)

But if C was 30, how many times could you put B (5) into it?

30/5 = 6

You would need 6 boxes of B to make 30 grams of C.
5 0
3 years ago
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What is the empirical formula of a compound that is 41.4% Strontium, 13.24%
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Answer:

Empirical Formula N2O6Sr Strontium Nitrate

Explanation:

N=13.2% O=45.4% Sr=41.4%

6 0
3 years ago
State whether it would be worthwhile to investigate finding a catalyst to use in this reaction under standard conditions and exp
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Yes, it will be worthwhile to investigate finding a catalyst to use in this reaction under standard conditions because it is negative.

<h3>What is a Catalyst?</h3>

This is a substance which speeds up the rate of a chemical reaction by lowering the activation energy.

ΔG being negative indicates a a slow reaction which is why a catalyst under standard conditions should be used.

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3 0
2 years ago
The label shown above contains information about some harmful effects of acetone.A group of students plans to use acetone to rin
Fed [463]

Answer:

<u>Heating water with an open flame</u>

<u>Explanation:</u>

Remember, we are told in the label that Acetone is a "flammable liquid and vapor." <em>Being flammable means the substance can easily be set on fire</em>, and we would expect an open flame from heating water to trigger an explosion (a disaster) in which the Acetone is set on fire causing life-threatening dangers to the second group of students.

8 0
3 years ago
What is the empirical formula of a compound containing 40.0% sulfur and 60.0% oxygen by mass?
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in order to determine empirical formula we have to determine the mole ratio of the given elements

Let the total mass of the compound is 100g

as given that the compound has 40% sulfur , so mass of sulfur = 40g

as given that the compound has 60% oxygen, so mass of oxygen = 60g

let us calculate the moles of each element

Moles of sulfur = mass / atomic mass = 40 / 32 = 1.25

moles of oxygen = mass / atomic mass = 60/ 16 = 3.75

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So empirical formula will be SO₃

3 0
3 years ago
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