<h2>
Answer:</h2>
cos 28°cos 62°– sin 28°sin 62° = 0
<h2>
Step-by-step explanation:</h2>
From one of the trigonometric identities stated as follows;
<em>cos(A+B) = cosAcosB - sinAsinB -----------------(i)</em>
We can apply such identity to solve the given expression.
<em>Given:</em>
cos 28°cos 62°– sin 28°sin 62°
<em>Comparing the given expression with the right hand side of equation (i), we see that;</em>
A = 28°
B = 62°
<em>∴ Substitute these values into equation (i) to have;</em>
<em>⇒ cos(28°+62°) = cos28°cos62° - sin28°sin62°</em>
<em />
<em>Solve the left hand side.</em>
<em>⇒ cos(90°) = cos28°cos62° - sin28°sin62°</em>
⇒ 0 = <em>cos28°cos62° - sin28°sin62° (since cos 90° = 0)</em>
<em />
<em>Therefore, </em>
<em>cos28°cos62° - sin28°sin62° = 0</em>
<em />
<em />
Answer:
kdkidn ir ejido la la la ayudara a las dos ángulos congruentes y q
To round 0.472 to the nearest tenth consider the hundredths' value of 0.472, which is 7 and equal or more than 5. Therefore, the tenths value of 0.472 increases by 1 to 5.
So, the answer would be 0.5.
<u>I hope this helped!</u>
The first is in the form y=Mx+b where m is the slope and b is the y-intercept. Start at 600 on the y-axis and graph with a slope of six. The second is in the same form but the y-intercept is 0, so start at the origin and graph with a slope of 8. The last is in the form y=b+mx, so start at 1300 and graph with a slope of 3. Remember, slope is rise/run or (change in y)/(change in x). Since the domain and range start at 0 these graphs will only be in the first quadrant with an x limit of 650 and a y limit of 1500.
