3 years ago

The equation of a line is x = -4. Will this produce a horizontal, vertical, or diagnol line?

Mathematics

1 answer:

Nuetrik [128]3 years ago

3 0

Vertical because the line passed through -4 on the x axis

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ASAP: I need as soon as possible with this question I have taken a picture of. If you could tell me how to do it and the answer,

VladimirAG [237]

Answer:

The answer to your question is h = 125.85 ft = 126 ft

Step-by-step explanation:

Process

1.- Determine two equations to solve the problem

$tan 14 = \frac{h}{x}$ (1)

$tan 47 = \frac{h}{x - 386}$ (2)

from (1) h = xtan14

substitute in (2) tan 47 = $\frac{xtan14}{x - 386}$

solve for x tan47(x - 386) = xtan14

1.07x - 413.9 = 0.25x

1.07x - 0.25x = 413.9

0.82x = 413.9

x = 413.9/0.82

x = 504.76 ft

2.- Calculate h

h = 504.76 tan 14

h = 125.85 ft = 126 ft

4 0

3 years ago

Analysis of an accident scene indicates a car was traveling at a velocity of 69.5 mph (31.1 m/s) along the positive x-axis at th

STatiana [176]

We can find the acceleration via

${v_f}^2-{v_i}^2=2a\Delta x$

We have

$\left(5.20\dfrac{\rm m}{\rm s}\right)^2-\left(31.1\dfrac{\rm m}{\rm s}\right)^2=2a(115\,\mathrm m)$

$\implies\boxed{a=-4.09\dfrac{\rm m}{\mathrm s^2}}$

Then by definition of average acceleration,

$a_{\rm ave}=\dfrac{v_f-v_i}t$

so that

$-4.09\dfrac{\rm m}{\mathrm s^2}=\dfrac{5.20\frac{\rm m}{\rm s}-31.1\frac{\rm m}{\rm s}}t$

$\implies\boxed{t=6.33\,\mathrm s}$

We alternatively could have found the time without knowing the acceleration. Since acceleration is constant, the average velocity is

$v_{\rm ave}=\dfrac{x_f-x_i}t=\dfrac{v_f+v_i}2$

Then

$\dfrac{115\,\rm m}t=\dfrac{5.20\frac{\rm m}{\rm s}+31.1\frac{\rm m}{\rm s}}2$

$\implies\boxed{t=6.33\,\mathrm s}$

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3 years ago

What's y=-4+15 in standard form

kotykmax [81]

Answer:

y=1.1×10¹

Step-by-step explanation:

y=-4+15

y=11

y=1.1×10¹

5 0

2 years ago