Answer:
x = –7, x = 2, or x = 4 are factors of f(x).
Step-by-step explanation:
Given : f(x) = 5x³ +5x²-170x +280 and x + 7 is one factor .
To find : What are all the roots of the function.
Solution : f(x) = 5x³ +5x²-170x +280 .
We have given that x + 7 is factor that mean x = -7 is factor of f(x )
When we divide f(x) by x +7 we get
5x² -30x +40 =0
Taking common 5 from equation
5( x² -6x +8) =0
On dividing by 5 both sides
x² -6x +8 = 0
On factoring
x² -2x -4x +8 = 0.
Taking common x from first two terms and -4 from last two terms
x ( x -2) -4 (x -2) = 0
On grouping
(x-2) (x-4) = 0
x -2 =0
x =2
x-4 =0
x = 4
Therefore, x = –7, x = 2, or x = 4 are factors of f(x).
Answer:
a = 1, b = 7
Step-by-step explanation:
Given the 2 equations
3a + 6b = 45 → (1)
2a - 2b = - 12 → (2)
Multiply (2) by 3 and add to (1) to eliminate the term in b
6a - 6b = - 36 → (3)
Add (1) and (3) term by term
(3a + 6a) + (6b - 6b) = (45 - 36)
9a = 9 ( divide both sides by 9 )
a = 1
Substitute a = 1 in either (1) or (2) and solve for b
(1) → 3 + 6b = 45 ( subtract 3 from both sides )
6b = 42 ( divide both sides by 6 )
b = 7
Divide 6 by 3
3 goes into 6, 2 times so one apple costs $2
Answer:
-14a -14- 27/a-2 hope this helps
Step-by-step explanation:
