Answer:
The Jar of peanut butter
Step-by-step explanation:
The easiest way to do this is to calculate price per ounce of each unit.
We'll assign the 12 ounce jar to the variable s and the bulk to the variable b.
First create an equation to find the values of each product per ounce.
Since the 12 ounce jar(s) sells for 3.96 we can say it is 3.96 for every 12 ounces, or s = 3.96/12oz.
Simplify this equation and you get s = 0.33 per ounce.
For b we need to convert pounds to ounces.
There are 16 ounces per pound so the equation we get is:
b = 5.50/16oz
Simplified we get:
b = about 0.34/oz
The smaller jar has a rate of $0.33/oz
The bulk has a rate of $0.34/oz
This means the answer is b. The jar of peanut butter has a cheaper unit rate.
1044
-36=c/-29
Multiply -29 to both sides.
c=1044
14,28,42,56,70,84,98,112,126,140,154,168,182,196,210,224,238,252,266,280,294,308,
Is that enough?
Answer:
Let v(t) be the velocity of the car t hours after 2:00 PM. Then 
. By the Mean Value Theorem, there is a number c such that 
with 
. Since v'(t) is the acceleration at time t, the acceleration c hours after 2:00 PM is exactly 
.
Step-by-step explanation:
The Mean Value Theorem says,
Let be a function that satisfies the following hypotheses:
- f is continuous on the closed interval [a, b].
- f is differentiable on the open interval (a, b).
Then there is a number c in (a, b) such that
Note that the Mean Value Theorem doesn’t tell us what c is. It only tells us that there is at least one number c that will satisfy the conclusion of the theorem.
By assumption, the car’s speed is continuous and differentiable everywhere. This means we can apply the Mean Value Theorem.
Let v(t) be the velocity of the car t hours after 2:00 PM. Then 
and 
(note that 20 minutes is 
of an hour), so the average rate of change of v on the interval ![[0 \:h, \frac{1}{3} \:h]](https://tex.z-dn.net/?f=%5B0%20%5C%3Ah%2C%20%5Cfrac%7B1%7D%7B3%7D%20%5C%3Ah%5D)
is
We know that acceleration is the derivative of speed. So, by the Mean Value Theorem, there is a time c in 
at which .
c is a time time between 2:00 and 2:20 at which the acceleration is .
Answer:
x = 11.85
Step-by-step explanation:
x^2+(x-4)^2=202
x^2+(x-4)(x-4)=202
x^2 + x^2 - 4x - 4x + 16 = 202
2x^2 - 8x + 16 = 202
2x^2 - 8x - 186 = 0
Apply the quadratic equation and you'll get x as:
x=11.85 or x=-7.85
x cannot be negative
therefore x = 11.85
