Question

Hi Brainly Community!

Answer 1

Step-by-step explanation:

$\frac{ {8}^{3x} }{ {8}^{2x + 1} }$

${8}^{3x - 2x - 1}$

${8}^{x - 1}$

${8}^{x - 1} = {8}^{9}$

$so \: x - 1 = 9$

$so \: x = 10$