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2 years ago

13

Find the value of x.

1 answer:

inessss [21]2 years ago

5 0

Answer:

7

Step-by-step explanation:

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Someone please help with this geometry question!!!

ahrayia [7]

What is the number down their?

6 0

3 years ago

The mathematics department of a college has 15 male professors, 9 female professors, 6 male teaching assistants, and 12 female t

Vesnalui [34]

Given:

The number of male professors = 15.

The number of female professors = 9.

The number of male teaching assistants = 6.

The number of female teaching assistants = 12.

A person is selected randomly from the group.

Required:

We need to find the probability that the selected person is a professor or a male.

Explanation:

The total number of people in the group = 15+9+6+12 = 42

n(S) =The total number of people in the group

$n(S)=42$

Let A be the event that the selected person is a professor or a male.

The number of people who are professors or male = 15+9+6 = 30

n(A)= The number of people who are professors or male.

$n(A)=30$

Let P(A) be the probability that the selected person is a professor or a male.

$P(A)=\frac{n(A)}{n(S)}$ $P(A)=\frac{30}{42}$ $P(A)=\frac{15}{21}=\frac{5}{7}$

Final answer:

The probability that the selected person is a professor or a male is 5/7.

7 0

1 year ago

A committee of 4 people is randomly selected from a group of 5 Republicans and 6 Democrats. What is the probability that the com

IgorLugansk [536]

We have 5 Republican Candidates and 6 Democratic Candidates

We have a total 11 candidates to choose from

First pick of Democratic Candidates = 6/11
Second pick of Democratic Candidates = 5/10
Third pick of Democratic Candidates = 4/9
Fourth pick of Democratic Candidates = 3/8

The probability of four Democratic candidates in the committee is
$\frac{6}{11}$ × $\frac{5}{10}$ × $\frac{4}{9}$ × $\frac{3}{8}$ = $\frac{360}{7920} = \frac{1}{22}$

4 0

3 years ago

Pls pls pls help

Natasha_Volkova [10]

Answer:

Parallelograms I, II, and IV

Step-by-step:

Area of parallelograms:

I. A=3*5=15 units squared

II. A=5*3=15 units squared

III. A=4*4=16 units squared

IV. A=5*3=15 units squared

So, parallelograms I, II, and IV have the same area of 15 units squared.

5 0

3 years ago

Two vectors A⃗ and B⃗ are at right angles to each other. The magnitude of A⃗ is 5.00. What should be the length of B⃗ so that th

creativ13 [48]

Answer:

Length of B is 7.4833

Step-by-step explanation:

The vector sum of A and B vectors in 2D is

$C=A+B=(a_1+b_1,a_2+b_2)$

And its magnitude is:

$C=\sqrt{(a_1+b_1)^2+(a_2+b_2)^2} =9$

Where

$a_1=Asinx$

$a_2=Acosx$

$b_1=Bsin(x+90)$

$b_2=Bcos(x+90)$

Using the properties of the sum of two angles in the sin and cosine:

$b_1=Bsin(x+90)=B(sinx*cos90+sin90*cosx)=Bcosx$

$b_2=Bcos(x+90)=B(cosx*cos90-sinx*sin90)=-Bsinx$

Sustituying in the magnitud of the sum

$C=\sqrt{(Asinx+Bcosx)^2+(Acosx-Bsinx)^2} =9$

$C=\sqrt{A^2sin^2x+2ABsinxcosx+B^2cos^2x+A^2cos^2x-2ABsinxcosx+B^2sin^2x} =9$

$C=\sqrt{A^2(sin^2x+cos^2x)+B^2(cos^2x+sin^2x)}$

$C=\sqrt{A^2+B^2} =9$

Solving for B

$A^2+B^2 =9^2$

$B^2 =9^2-A^2$

Sustituying the value of the magnitud of A

$B^2=81-5^2=81-25=56$

$B= 7. 4833$

8 0

3 years ago