Answer:
Both get the same results that is,
![\left[\begin{array}{ccc}140\\160\\200\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D140%5C%5C160%5C%5C200%5Cend%7Barray%7D%5Cright%5D)
Step-by-step explanation:
Given :
![\bf M=\left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]](https://tex.z-dn.net/?f=%5Cbf%20M%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cfrac%7B1%7D%7B5%7D%26%5Cfrac%7B1%7D%7B5%7D%26%5Cfrac%7B2%7D%7B5%7D%5C%5C%5Cfrac%7B2%7D%7B5%7D%26%5Cfrac%7B2%7D%7B5%7D%26%5Cfrac%7B1%7D%7B5%7D%5C%5C%5Cfrac%7B2%7D%7B5%7D%26%5Cfrac%7B2%7D%7B5%7D%26%5Cfrac%7B2%7D%7B5%7D%5Cend%7Barray%7D%5Cright%5D)
and initial population,
![\bf P=\left[\begin{array}{ccc}130\\300\\70\end{array}\right]](https://tex.z-dn.net/?f=%5Cbf%20P%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D130%5C%5C300%5C%5C70%5Cend%7Barray%7D%5Cright%5D)
a) - After two times, we will find in each position.
![P_2=[P].[M]^2=[P].[M].[M]](https://tex.z-dn.net/?f=P_2%3D%5BP%5D.%5BM%5D%5E2%3D%5BP%5D.%5BM%5D.%5BM%5D)
![M^2=\left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]\times \left[\begin{array}{ccc}\frac{1}{5}&\frac{1}{5}&\frac{2}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{1}{5}\\\frac{2}{5}&\frac{2}{5}&\frac{2}{5}\end{array}\right]](https://tex.z-dn.net/?f=M%5E2%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cfrac%7B1%7D%7B5%7D%26%5Cfrac%7B1%7D%7B5%7D%26%5Cfrac%7B2%7D%7B5%7D%5C%5C%5Cfrac%7B2%7D%7B5%7D%26%5Cfrac%7B2%7D%7B5%7D%26%5Cfrac%7B1%7D%7B5%7D%5C%5C%5Cfrac%7B2%7D%7B5%7D%26%5Cfrac%7B2%7D%7B5%7D%26%5Cfrac%7B2%7D%7B5%7D%5Cend%7Barray%7D%5Cright%5D%5Ctimes%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%5Cfrac%7B1%7D%7B5%7D%26%5Cfrac%7B1%7D%7B5%7D%26%5Cfrac%7B2%7D%7B5%7D%5C%5C%5Cfrac%7B2%7D%7B5%7D%26%5Cfrac%7B2%7D%7B5%7D%26%5Cfrac%7B1%7D%7B5%7D%5C%5C%5Cfrac%7B2%7D%7B5%7D%26%5Cfrac%7B2%7D%7B5%7D%26%5Cfrac%7B2%7D%7B5%7D%5Cend%7Barray%7D%5Cright%5D)
![=\frac{1}{25} \left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right]](https://tex.z-dn.net/?f=%3D%5Cfrac%7B1%7D%7B25%7D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%267%267%5C%5C8%268%268%5C%5C10%2610%2610%5Cend%7Barray%7D%5Cright%5D)
![\therefore\;\;\;\;\;\;\;\;\;\;\;P_2=\left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right] \times\left[\begin{array}{ccc}130\\300\\70\end{array}\right] = \left[\begin{array}{ccc}140\\160\\200\end{array}\right]](https://tex.z-dn.net/?f=%5Ctherefore%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3B%5C%3BP_2%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%267%267%5C%5C8%268%268%5C%5C10%2610%2610%5Cend%7Barray%7D%5Cright%5D%20%5Ctimes%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D130%5C%5C300%5C%5C70%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D140%5C%5C160%5C%5C200%5Cend%7Barray%7D%5Cright%5D)
b) - With in migration process, 500 people are numbered. There will be after a long time,
![After\;inifinite\;period=[M]^n.[P]](https://tex.z-dn.net/?f=After%5C%3Binifinite%5C%3Bperiod%3D%5BM%5D%5En.%5BP%5D)
![Then,\;we\;get\;the\;same\;result\;if\;we\;measure [M]^n=\frac{1}{25} \left[\begin{array}{ccc}7&7&7\\8&8&8\\10&10&10\end{array}\right]](https://tex.z-dn.net/?f=Then%2C%5C%3Bwe%5C%3Bget%5C%3Bthe%5C%3Bsame%5C%3Bresult%5C%3Bif%5C%3Bwe%5C%3Bmeasure%20%5BM%5D%5En%3D%5Cfrac%7B1%7D%7B25%7D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D7%267%267%5C%5C8%268%268%5C%5C10%2610%2610%5Cend%7Barray%7D%5Cright%5D)
![=\left[\begin{array}{ccc}140\\160\\200\end{array}\right]](https://tex.z-dn.net/?f=%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D140%5C%5C160%5C%5C200%5Cend%7Barray%7D%5Cright%5D)
42.
As
1 dozen is 12 eggs, 3 dozens of the eggs is 12×3=36.
half of a dozens is 6 so
36+6 =42
A. v.kubus = s×s×s
= 6×6×6
= 216
b. v.kubus = s×s×s
= 5,6×5,6×5,6
= 175,616
c. v.kubus = s×s×s
= 34×34×34
=39304
"The discriminant is prime?" I haven't heard that one before.
Here are the general rules:
1. a positive discriminant results in two real, unequal roots.
2. a zero discr. results in two real, equal roots.
3. a negative discr. results in two complex roots, which sometimes means two imaginary roots.
Answer:
5.0×10⁷
Step-by-step explanation:
(3÷6)×(10⁴÷10^-4)
(0.5)×(10⁸)
5.0×10^-1×10⁸
5.0×10⁷
