Find the value of x.

Leokris [45]

A. Categorical
b. I think walking group (I’m not sure)
c. Bar graph

6 0

2 years ago

A fitted multiple regression equation is Y = 28 + 5X1 - 4X2 + 7X3 + 2X4. When X1 increases 2 units and X2 increases 2 units as w

ad-work [718]

Answer:

A. Increase by 2

Step-by-step explanation:

Given that a fitted multiple regression equation is

$Y = 28 + 5X_1 -4X_2 + 7X_3 + 2X_4$

This is a multiple regression line with dependent variable y and independent variables x1, x2, x3 and x4

The coefficients of independent variables represent the slope.

In other words the coefficients represent the rate of change of y when xi is changed by 1 unit.

Given that x3 and x4 remain unchanged and x1 increases by 2 and x2 by 2 units

Since slope of x1 is 5, we find for one unit change in x1 we can have 5 units change in y

i.e. for 2 units change in x1, we expect 10 units change in Y

Similarly for 2 units change in x2, we expect -2(4) units change in Y

Put together we have

$10-8 =2$ change in y

Since positive 2, there is an increase by 2

A. Increase by 2

5 0

3 years ago

Why is cosine positive in the 4th quadrant and sine isn’t?

kari74 [83]

Answer:

Because sine can only be positive in quadrant II according to the CAST rule.

8 0

3 years ago

John and Jane are married. The probability that John watches a certain television show is .7. The probability that Jane watches

ikadub [295]

a) The probability that both John and Jane watch the show is 0.12.

b.The probability that Jane watches the show, given that John does is 0.1714.

c)They do watch show independent of each other.

Step-by-step explanation:

Here, as given in the question:

Probability that John watches a certain show = 0.7 ⇒ P(J) = 0.7

Probability that Jane watches a certain show = 0.3 ⇒ P(Je) = 0.3

Probability that John watches a certain show given Jane watches it to

= 0.4 ⇒ P(J/Je) = 0.4

a. ) Here, we need to find the probability of both Jane and John watching a show , P(J∩Je)

Now, by BAYES THEOREM:

$P(J/Je) = \frac{P(J \cap Je)}{P(Je)}$

$\implies 0.4 = \frac{P(J \cap Je)}{0.3} \\\implies P(J \cap Je) = 0.4 \times 0.3 = 0.12$

Hence the probability that both John and Jane watch the show is 0.12.

b.) The probability that Jane watches the show, given that John does is P(J/Je)

By BAYES Theorem:

$P(Je/J) = \frac{P(J \cap Je)}{P(J)}\\\implies P(Je/J) = \frac{0.12}{0.7} = 0.1714$

Hence, the probability that Jane watches the show, given that John does is 0.1714.

c) As we can see P(Jane ∩ John) = 0.12

So, the probability of both of them seeing the show TOGETHER is 0.12.

Hence, they do watch show independent of each other and the probability of doing that is 1.0.12 = 0.88

7 0

3 years ago

In the triangle EFG,

MariettaO [177]

Answer:

$4.\ \sin E = \cos G$

Step-by-step explanation:

Given

$\triangle EFG$

$\angle F = 90^o$ --- right angle

Required

Which of the options is true

In a triangle, we have:

$\angle E + \angle F + \angle G = 180^o$ --- angles in a triangle

Substitute $\angle F = 90^o$

$\angle E + 90^o + \angle G = 180^o$

Collect like terms

$\angle E + \angle G = 180^o -90^o$

$\angle E + \angle G =90^o$

This implies that E and G are complementary angles.

For complementary angles, E and G;

$\sin E = \cos G$ and $\sin G = \cos E$

<em>Hence, (4) is true</em>

7 0

2 years ago