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sesenic [268]
2 years ago
6

David's phone bill each month is $30. He is also charged $0.10 per GB of data he uses. If his phone bill in july was $42, how ma

ny GB of data did he use in July?
Mathematics
1 answer:
Bogdan [553]2 years ago
8 0

Answer:

80$

Step-by-step explanation:

He’d payed that much

You might be interested in
A rock climber climbs at a rate of 720 feet per hour. Write and solve an equation to find the number of minutes m it takes for t
Lorico [155]

Answer:

The equation is <em>y</em>=12<em>x</em>. It takes 24 minutes for the rock climber to get to 288 feet.

Step-by-step explanation:

Since we know there are 60 minutes in an hour, we can divide 720 by 60. This gives us 12. Therefore, for every minute, the rock climber gets 12 feet higher. Assuming <em>y </em>is the height in feet, and <em>x</em> is the time in minutes, we can create the equation <em>y</em>=12<em>x</em>. Now, to find how long it takes to get to 288 feet, we will substitute y with 288.

288=12<em>x</em>

288/12 = 12x/12

24 = x

Now, we have time in minutes that it takes to get to 288 feet.

Hope this helps!

7 0
3 years ago
Why you find 39 when you estimate difference 206and 167<br> Thinks
Mama L [17]

You get 39 as an answer because you're taking 209 minus 167 and 39 is the answer that you get.

7 0
3 years ago
Find the number a for which x=5 is a solution of the given equation.
vfiekz [6]

Step-by-step explanation:

x + 8a = 25 + ax - 7a

x = 5

5 + 8a = 25 + 5a - 7a

5 + 8a = 25 - 2a

5 + 10a = 25

10a = 20

a = 2

3 0
2 years ago
The producer of a certain bottling equipment claims that the variance of all its filled bottles is .027 or less. A sample of 30
o-na [289]

Answer:

p_v = P(\chi^2_{29}>42.963)=1-0.954=0.0459

b. between .025 and .05

Step-by-step explanation:

Previous concepts and notation

The chi-square test is used to check if the standard deviation of a population is equal to a specified value. We can conduct the test "two-sided test or a one-sided test".

\bar X represent the sample mean

n = 30 sample size

s= 0.2 represent the sample deviation

\sigma_o =\sqrt{0.027}=0.164 the value that we want to test

p_v represent the p value for the test

t represent the statistic

\alpha= significance level

State the null and alternative hypothesis

On this case we want to check if the population standard deviation is less than 0.027, so the system of hypothesis are:

H0: \sigma \leq 0.027

H1: \sigma >0.027

In order to check the hypothesis we need to calculate the statistic given by the following formula:

t=(n-1) [\frac{s}{\sigma_o}]^2

This statistic have a Chi Square distribution distribution with n-1 degrees of freedom.

What is the value of your test statistic?

Now we have everything to replace into the formula for the statistic and we got:

t=(30-1) [\frac{0.2}{0.164}]^2 =42.963

What is the approximate p-value of the test?

The degrees of freedom are given by:

df=n-1= 30-1=29

For this case since we have a right tailed test the p value is given by:

p_v = P(\chi^2_{29}>42.963)=1-0.954=0.0459

And the best option would be:

b. between .025 and .05

6 0
3 years ago
Simplify (5x - 7y) - ( x + 3y)
ruslelena [56]
This equation simplified is: 14x - 10y



4 0
3 years ago
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