Question

For the reaction

Answer 1

Answer:

A(g)+2B(g)→C(g)+D(g) K

C

=10

12

At 0.5 1 0.5 0.5

t=0

At 0.5−α 1−2α 0.5+α 3.5+α

t=t

eq

Since K

C

=10

12

very large α≈0.5

Let 0.5−α be (x)

So [A]=x

[B]=x

[C]≈1

[D]≈4

K

C

=

[B]

2

[A]

[C][D]

4x

2

×x

1×4

=10

+12

x=10

−4

[B]=2x=2×10

−4

M