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Firdavs [7]
3 years ago
11

Mercury is a liquid meteal but it is not hard? how can we say it is a metal

Chemistry
1 answer:
NNADVOKAT [17]3 years ago
7 0
What's the problem ? Hardness is not the definition of a metal. You need to expand your thinking. EVERY element is solid, liquid, and gas, over different ranges of temperature ... including all of the metals. There are only TWO elements that are liquid AT ROOM TEMPERATURE, and mercury is one of them. But on a mild day at the south pole, mercury is solid too.
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A car travels 200 miles in 4 hours calculate the cars speed
Vaselesa [24]

Answer:

50 mph

Explanation:

To figure out how many miles per hour this car is going, we divide the distance traveled by the time it took.

200 ÷ 4 = 50

7 0
2 years ago
How many moles are in 20g of potassium (K)?
otez555 [7]

Explanation:

Hi for this one u just need to remember and use the equation.

moles =  \frac{mass}{mr}

then u find mr of potassium which is 39.1.

then u do

\frac{20}{39.1}

you get the answer as 0.5115 write ur answer to 3 significant figures which will be 0.512 moles .

hope this helps :)

7 0
3 years ago
HELPP PLEASEEE I REALLY NEED IT!!!!!!!!
SSSSS [86.1K]
Answer:

Americium is: [Rn]5f^7s^2

Bismuth is: [Xe]6s^24f^145d^106p^3

Tin is: [Kr]4d^105s^25p^2

Vanadium is: [Ar]3d^34s^2

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8 0
3 years ago
Can anyone please help me find molar masses of compounds. For example Copper (ll) sulfate (CuSO4)
Alina [70]

Answer:

Explanation:

You would have to add up the atomic masses of all the compounds in the compound, making sure you include how many molecules of each are in the compound

For example, in CuSOA we have 1 molecule of Cu and S, as 4 molecules of O

The atomic masses are as follows:

Cu = 63.55 u

S = 32.065 u

O = 15.99 units

This is how we would add it up:

(Atomic mass of Cu) + (Atomic mass of S) + 4(Atomic Mass of O)

(63.55) + (32.065) + 4(15.99)

(63.55) + (32.065) + 63.96

= 159.575 u

7 0
2 years ago
Read 2 more answers
In a neutralization reaction, 24.6 mL of 0.300 M H2SO4(aq) reacts completely with 20.0 mL of NaOH(aq). The products are Na2SO4(a
stiv31 [10]

Answer : The concentration of the NaOH solution is, 0.738 M

Explanation :

To calculate the concentration of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=0.300M\\V_1=24.6mL\\n_2=1\\M_2=?\\V_2=20.0mL

Putting values in above equation, we get:

2\times 0.300M\times 24.6mL=1\times M_2\times 20.0mL

M_2=0.738M

Thus, the concentration of the NaOH solution is, 0.738 M

7 0
3 years ago
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