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3 years ago

What is the main FUNCTION of the digestive system?

Chemistry

1 answer:

Gemiola [76]3 years ago

8 0

The main function of the digestive system is to break food down

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Iron and oxygen !!!!!

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Which Body system works alone to maintain homeostasis? (pls help)

Yanka [14]

Answer:

circulatory system

Explanation:

Your circulatory system delivers oxygen-rich blood to your bones. Meanwhile, your bones are busy making new blood cells. Working together, these systems maintain internal stability and balance, otherwise known as homeostasis.

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Sally does the work in 2.3 hours and Pete does 2.5

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Pete because 2.5 x 2.3 is faster

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If a gas is cooled from 425.0K to 275.15K and the volume is kept constant what final pressure would result if the original press

mr Goodwill [35]

Answer: 498.51mmHg

Explanation:

First let us analyse what was given from the question:

T1 = 425K

T2 = 275.15K

P1 = 770 mmHg

P2 =?

Using the general gas equation

P1V1/T1 = P2V2/T2

But we were told from the question that the volume is constant. So, our equation becomes:

P1/T1 = P2/T2

770/425 = P2 /275.15

Cross multiply to express in linear form:

P2 x 425 = 770 x 275.15

Divide both side by 425, we have:

P2 = (770 x 275.15) /425

P2 = 498.51mmHg

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3 years ago

Calculate the ph of a dilute solution that contains a molar ratio of potassium acetate to acetic acid (pka ???? 4.76) of (a) 2:1

givi [52]

According to Hasselbach-Henderson equation:

$pH=pK_{a}+log\frac{[A^{-}]}{[HA]}$

Here, $[A^{-}]$ is concentration of conjugate base and [HA] is concentration of acid.

In the given problem, conjugate base is $CH_{3}COOK$ and acid is $CH_{3}COOH$ thus, Hasselbach-Henderson equation will be as follows:

$pH=pK_{a}+log\frac{[CH_{3}COOK]}{[CH_{3}COOH]}$ ...... (1)

(a) Ratio of concentration of potassium acetate and acetic acid is 2:1 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=2$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{2}{1}=5.06$

Therefore, pH of solution is 5.06.

(b) Ratio of concentration of potassium acetate and acetic acid is 1:3 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=\frac{1}{3}$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{1}{3}=4.28$

Therefore, pH of solution is 4.28.

(c)Ratio of concentration of potassium acetate and acetic acid is 5:1 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=\frac{5}{1}$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{5}{1}=5.45$

Therefore, pH of solution is 5.45.

(d) Ratio of concentration of potassium acetate and acetic acid is 1:1 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=1$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{1}{1}=4.76$

Therefore, pH of solution is 4.76.

(e) Ratio of concentration of potassium acetate and acetic acid is 1:10 thus,

$\frac{[CH_{3}COOK]}{[CH_{3}COOH]}=\frac{1}{10}$

Also, $pK_{a}=4.76$

Putting the values in equation (1),

$pH=4.76+log\frac{1}{10}=3.76$

Therefore, pH of solution is 3.76.

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3 years ago