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andre [41]
2 years ago
10

I need some help please

Mathematics
1 answer:
MA_775_DIABLO [31]2 years ago
5 0

The answer is A.

A negative x a negative equals a positive so the square root of a negative value cannot be a negative value.

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Which triangle congruency postulate would you use to show ATW = AKW
svp [43]

Answer:

SSS

Step-by-step explanation:

Since AT and AK would assumingly be the same size to be equal to each other.

7 0
3 years ago
Read 2 more answers
P= ? , r=4%, t=3 months, I=$20
Scilla [17]
<span>Answer:

P = $ 2,000.00

Equation:
P = I / rt
Calculation:
First, converting R percent to r a decimal
r = R/100 = 4%/100 = 0.04 per year,
putting time into years for simplicity,
3 months ÷ 12 months/year = 0.25 years,
then, solving our equation

P = 20 / ( 0.04 × 0.25 ) = 2000
P = $ 2,000.00

The principal required to
accumulate interest of $ 20.00
on a rate of 4% per year for 0.25 years (3 months) is $ 2,000.00.
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3 0
3 years ago
answer plsss answer plss
nignag [31]

Answer:

b 2,3,8

Step-by-step explanation:

Y=234678

Z=278910

X=12358

234678910 n 12358

=238

8 0
2 years ago
X + y = 10<br> x - y = 2
lys-0071 [83]

Answer:

x=6

y=4

Step-by-step explanation:

just find the number that will match or u could just plug in one of those number and find other number

4 0
3 years ago
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A binary operation is defined on the set of real numbers ℝ by
zloy xaker [14]

Answer:

I. m = 2401

II. ((n+1) ∆ y)/n = 1/n[(n – y + 2)(n – y) + 1]

Step-by-step explanation:

I. Determination of m

x ∆ y = x² − 2xy + y²

2 ∆ − 5 = √m

2² − 2(2 × –5) + (–5)² = √m

4 – 2(–10) + 25 = √m

4 + 20 + 25 = √m

49 = √m

Take the square of both side

49² = m

2401 = m

m = 2401

II. Simplify ((n+1) ∆ y)/n

We'll begin by obtaining (n+1) ∆ y. This can be obtained as follow:

x ∆ y = x² − 2xy + y²

(n+1) ∆ y = (n+1)² – 2(n+1)y + y²

(n+1) ∆ y = n² + 2n + 1 – 2ny – 2y + y²

(n+1) ∆ y = n² + 2n – 2ny – 2y + y² + 1

(n+1) ∆ y = n² – 2ny + y² + 2n – 2y + 1

(n+1) ∆ y = n² – ny – ny + y² + 2n – 2y + 1

(n+1) ∆ y = n(n – y) – y(n – y) + 2(n – y) + 1

(n+1) ∆ y = (n – y + 2)(n – y) + 1

((n+1) ∆ y)/n = [(n – y + 2)(n – y) + 1] / n

((n+1) ∆ y)/n = 1/n[(n – y + 2)(n – y) + 1]

7 0
3 years ago
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