Answer:
By the Empirical Rule, 99.7% of the students have grade point averages that are between 1.28 and 3.8.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed(bell-shaped) random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 2.54
Standard deviation = 0.42.
Between 1.28 and 3.8?
1.28 = 2.54 - 3*0.42
So 1.28 is 3 standard deviations below the mean
3.8 = 2.54 + 3*0.42
So 3.8 is 3 standard deviations above the mean
By the Empirical Rule, 99.7% of the students have grade point averages that are between 1.28 and 3.8.
Answer:
The probability of picking a black card at random, from a deck with 3 black cards and 7 red ones is 0.3.
Step-by-step explanation:
We will assume that we have 3 black cards and 7 black cards, for a total of 10 cards. Since we are taking one card at random, we can assume that each card is equally likely to be drawn. We have the following event A: The drawn card is a black. We will find the probability of A as counting the number of outcomes that make A to occur and divide it by the total number of possibilities. We are drawing one card, so we have 10 possibilities to be picked. Out of those 10, only 3 cards are black, hence we have 3 possibilites of picking a black card.
Then,
P(A) = 3/10 = 0.3.
Answer:
The height is 10in
Step-by-step explanation:
If you need to calculate the volume, you need to know the formula. The formula is length x width x height. You have the length and width, so you need the height. 2.5in x 15in x 10in = 375 in^3. You may ask why it is inches cubed instead of inches. It is inches cubed because you multiplied three inches together.
Answer:
x + 5
Step-by-step explanation:
I'm not sure how to explain this, sorry!
Answer:
He drew a scalene triangle
Step-by-step explanation:
A scalene triangle is where all side measure and all angle measure are different.
