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Dima020 [189]
1 year ago
5

Find the value of z.

Mathematics
1 answer:
omeli [17]1 year ago
8 0

Applying the angle of intersecting chords theorem, the value of z is: D. 100.

<h3>What is the Angle of Intersecting Chords Theorem?</h3>

According to the angle of intersecting chords theorem, in a circle like the one shown in the image above, where two chords intersect to form vertical angles, the theorem states that the angle formed equals half of the sum of the measures of the arcs intercepted by the angles.

Applying the angle of intersecting chords theorem, let's find x first:

73 = 1/2(96 + x)

Multiply both sides by 2

2 × (73) = 1/2(96 + x) × 2

146 = 96 + x

Subtract both sides by 96

146 - 96 = 96 + x - 96

50 = x

x = 50°

Therefore:

x + z + 96 + 114 = 360° [full circle measure]

Plug in the value of x

50 + z + 96 + 114 = 360

z + 260 = 360

Subtract both sides by 260

z + 260 - 260 = 360 - 260

z = 100°

The answer is: D. 100°.

Learn more about the angle of intersecting chords theorem on:

brainly.com/question/23732231

#SPJ1

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IgorC [24]

Hello!

Let's write some important information contained in the exercise:

• hotdogs: $2.59 (,x,)

,

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He needs 11 packages. Let's write it:

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He spent a total of $39.29. We can write it as:

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Now, let's solve these two equations as a linear system:

\begin{cases}x+y=11\text{ equation A} \\ 2.59x+5.29y=39.29\text{ equation B}\end{cases}

First, let's isolate x in equation A:

\begin{gathered} x+y=11 \\ x=11-y \end{gathered}

Now, we will replace where's x by 11-y in equation B:

\begin{gathered} 2.59x+5.29y=39.29 \\ 2.59(11-y)+5.29y=39.29 \\ 28.49-2.59y+5.29y=39.29 \\ -2.59y+5.29y=39.29-28.49 \\ 2.7y=10.8 \\ y=\frac{10.8}{2.7} \\  \\ y=4 \end{gathered}

As I called the hamburgers as 'y', we know that he bought 4 packages of hamburgers.

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Step-by-step explanation:

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The rational root theorem states that the rational roots of a polynomial can only be in the form p/q, where p divides the constant term, and q divides the leading term.

In your case, both the leading term 5 and the constant term 11 are primes, so their only divisors are 1 and themselves.

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