First you have to know BODMAS/BIDMAS (idk if all schools teach it like this) but this is the order in which you complete questions so it’s Brackets, Indices, Division/Multiplication, Addition/Subtraction
a) 5^2 is 5x5 which equals 25 1 to the power of anything is always 1 and 2^4 is 2x2x2x2 which is 16
So 5^2-1^5x2^4 = 25-1x16 which is then 25-16 = 9
b) 7^2+4^3 divided by 2^5 so 7^2 is 7x7 which = 49 then 4^3 means 4x4x4 = 64 and 2^5 is 2x2x2x2x2 which equals 32 so
7^2+4^3 divides by 2^5 is 49+64/32 = 49+2 which is 51
Answer:
Step-by-step explanation:
Let the width be w centimeters.
Then the length = w + 7.
The area A is found from the length multiplied by the width.
330 = w(w + 7) = w^2 + 7w.
Now we can rearrange this equation to form a quadratic, as follows:
The factorization of the quadratic is:
(w + 22)(w - 15) = 0
Therefore we find that:
width = 15 centimeters
length = 22 centimeters
The answer is 1 whole and 1 /18. Hope this helps!
Answer:
(2, 7 )
Step-by-step explanation:
Given the 2 equations
y = 2x + 3 → (1)
y = 3x + 1 → (2)
Substitute y = 3x + 1 into (1)
3x + 1 = 2x + 3 ( subtract 2x from both sides )
x + 1 = 3 ( subtract 1 from both sides )
x = 2
Substitute x = 2 into either of the 2 equations for corresponding value of y
Substituting x = 2 into (1)
y = 2(2) + 3 = 4 + 3 = 7
Solution is (2, 7 )
