A) Work out the value of 5^2 – 1^5× 2^4b) Work out the value of 7^2 + 4^3 ÷ 2^5

Mathematics

1 answer:

NemiM [27]3 years ago

8 0

First you have to know BODMAS/BIDMAS (idk if all schools teach it like this) but this is the order in which you complete questions so it’s Brackets, Indices, Division/Multiplication, Addition/Subtraction
a) 5^2 is 5x5 which equals 25 1 to the power of anything is always 1 and 2^4 is 2x2x2x2 which is 16
So 5^2-1^5x2^4 = 25-1x16 which is then 25-16 = 9
b) 7^2+4^3 divided by 2^5 so 7^2 is 7x7 which = 49 then 4^3 means 4x4x4 = 64 and 2^5 is 2x2x2x2x2 which equals 32 so
7^2+4^3 divides by 2^5 is 49+64/32 = 49+2 which is 51

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so: (1/2^2)*(12*3)-5^3

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alexira [117]

We would have the following sample space:
(1, 1), (1, 2), (1, 3), (1, 4)
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natka813 [3]

Answer:

Part 1: $\frac{11-x}{5}$ or $\frac{11}{5}-\frac{x}{5}$

Part 2: $\frac{9}{5}$

Step-by-step explanation:

To start things off, you must put everything on the opposite side of y so that you only have the y variable left.

In this case, put x onto the other side, making it negative since it's flipped, so you get $5y=11-x$ (since the x is negative you're using subtraction from 11).